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3 years ago

- What is the equation of a cirde with a center

Mathematics

2 answers:

wlad13 [49]3 years ago

6 0

Answer:

Step-by-step explanation:

The equationof a circle:

$(x-h)^2+(y-k)^2=r^2$

(h, k) - center

r - radius

We have center = (4, -1) → h = 4, k = -1, and r = 9.

Substitute:

$(x-4)^2+(y-(-1))^2=9^2\\\\\huge\boxed{(x-4)^2+(y+1)^2=81}$

babymother [125]3 years ago

4 0

( C ) (x-4)+(+1=9 there is

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4 – (2y + 5) = 3(1 – 4y) show steps please

Lelu [443]

Answer/Step-by-step explanation:

Let's solve your equation step-by-step.

4−(2y+5)=3(1−4y)

Step 1: Simplify both sides of the equation.

4−(2y+5)=3(1−4y)

4+−1(2y+5)=3(1−4y)(Distribute the Negative Sign)

4+−1(2y)+(−1)(5)=3(1−4y)

4+−2y+−5=3(1−4y)

4+−2y+−5=(3)(1)+(3)(−4y)(Distribute)

4+−2y+−5=3+−12y

(−2y)+(4+−5)=−12y+3(Combine Like Terms)

−2y+−1=−12y+3

−2y−1=−12y+3

Step 2: Add 12y to both sides.

−2y−1+12y=−12y+3+12y

10y−1=3

Step 3: Add 1 to both sides.

10y−1+1=3+1

10y=4

Step 4: Divide both sides by 10.

10y

Answer:

y= 2/5

6 0

3 years ago

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Choose all the angles which are adjacent to < 3 Select all that apply

morpeh [17]

Answer:

A and B

Step-by-step explanation:

Adjacent angles are angles that share a common vertex

More specifically adjacent angles are next to each other.

The two angles that are next to ∠3 are ∠4 and ∠2 therefore the correct answer would be A and B

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2 years ago

A jumbo chocolate bar with a rectangular shape measures 11 centimeters in length, 8 centimeters in width, and 3 centimeters in

sesenic [268]

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3 years ago

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PtichkaEL [24]

Here you go pall, have a nice day

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3 years ago

Solve 5(2x-y) = 7x + 1 3(3x+y) = 5(x-y+12) using the elimination method thanks!

MaRussiya [10]

Answer:

{x = 7 , y = 4

Step-by-step explanation using elimination:

Solve the following system:

{5 (2 x - y) = 7 x + 1 | (equation 1)

{3 (3 x + y) = 5 (12 + x - y) | (equation 2)

Express the system in standard form:

{3 x - 5 y = 1 | (equation 1)

{4 x + 8 y = 60 | (equation 2)

Swap equation 1 with equation 2:

{4 x + 8 y = 60 | (equation 1)

{3 x - 5 y = 1 | (equation 2)

Subtract 3/4 × (equation 1) from equation 2:

{4 x + 8 y = 60 | (equation 1)

{0 x - 11 y = -44 | (equation 2)

Divide equation 1 by 4:

{x + 2 y = 15 | (equation 1)

{0 x - 11 y = -44 | (equation 2)

Divide equation 2 by -11:

{x + 2 y = 15 | (equation 1)

{0 x+y = 4 | (equation 2)

Subtract 2 × (equation 2) from equation 1:

{x+0 y = 7 | (equation 1)

{0 x+y = 4 | (equation 2)

Collect results:

Answer: {x = 7 , y = 4

8 0

3 years ago

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