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3 years ago

- What is the equation of a cirde with a center

Mathematics

2 answers:

wlad13 [49]3 years ago

6 0

Answer:

Step-by-step explanation:

The equationof a circle:

$(x-h)^2+(y-k)^2=r^2$

(h, k) - center

r - radius

We have center = (4, -1) → h = 4, k = -1, and r = 9.

Substitute:

$(x-4)^2+(y-(-1))^2=9^2\\\\\huge\boxed{(x-4)^2+(y+1)^2=81}$

babymother [125]3 years ago

4 0

( C ) (x-4)+(+1=9 there is

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a quadratic equation has a discriminant of 12. which could be the equation? a.0 = –x2 8x 2 b.0 = 2x2 6x 3 c.0 = –x2 4x 1 d.0 = 4

Norma-Jean [14]

Answer:

Option b which is $2x^2+6x+3=0$

Step-by-step explanation:

We have been given the discriminant 12

We have to choose the equation which will satisfy the given discriminant.

We will consider all the given equation one by one

First we will take option a which is $-x^2+8x+2=0$

Discriminant from the equation we will find by the formula

$D=b^2-4ac$

Here, a=-1,b=8 and c=2 on substituting the values we will get

$D=8^2-4(-1)(2)=72$

Hence, option a is incorrect.

Now, we will consider option b which is $2x^2+6x+3=0$

Here, a=2,b=6 and c=3 on substituting the values we get

$D=(6)^2-4(2)(3)=12$

Hence, option b is correct

Therefore, option b is the required answer.

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3 years ago

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Find the value of x² - x+1 when x=√3 -1, in the form a+b√3 where a and b are integers

lidiya [134]

Answer:

$6-3\sqrt{3}$

If you compare this to $a+b\sqrt{3}$ , then $a=6$ and $b=-3$ .

Step-by-step explanation:

We are given $x=\sqrt{3}-1$ and we are asked to find the value of $x^2-x+1$ .

So we will need to find $x^2$ .

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Expand using identity: $(x-a)^2=x^2-2ax+a^2$ .

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$6-3\sqrt{3}$

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4 years ago

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Answer:

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Step-by-step explanation:

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3 years ago

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zimovet [89]

Answer:

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Step-by-step explanation:

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