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Keith_Richards [23]
4 years ago
14

Bryan has 24 toy cars. Jason has 12 toy cars. What is the ratio of Jason’s toy cars to Bryan’s toy cars?

Mathematics
1 answer:
sergij07 [2.7K]4 years ago
3 0
12/24 = 1/2
answer is 1/2
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Slove for x : 3x + 4 = 9x + 3
andreyandreev [35.5K]

Answer:

x = 1/6

Step-by-step explanation:

3x + 4 = 9x + 3

3x + 1 = 9x

1 = 6x

1/6 = x

7 0
3 years ago
Read 2 more answers
The U.S. Mint produces quarters that weigh about 5.67 grams each. After the
lesantik [10]
  • The U.S. Mint makes commercial circulation coins including commemorative collection's coins including investor bullion coins.
  • In the case of circular coins, the quantities were measured in terms of figures for "production" numismatic categories in order "sales" and bullion "mintage" statistics.

\to \bold{|x-5.67|=0.02}\\\\

heaviest\bold{=5.69\ g\\\\}

lighest\bold{=5.65\ g\\\\}

Evaluating the each expression:  

\to \bold{q = -8}\\\\ \to \bold{r = -6}\\\\ \to \bold{t=3}

Learn more:

brainly.com/question/20845315

8 0
3 years ago
Subtract (-2x² +3x-5) from( 6x2 -4x+2)
Andreyy89

Answer:

8x² - 7x + 7

General Formulas and Concepts:

<u>Pre-Algebra</u>

  • Distributive Property

<u>Algebra I</u>

  • Combining Like Terms

Step-by-step explanation:

<u>Step 1: Define</u>

(6x² - 4x + 2) - (-2x² + 3x - 5)

<u>Step 2: Simplify</u>

  1. Distribute negative:                    6x² - 4x + 2 + 2x² - 3x + 5
  2. Combine like terms (x²):             8x² - 4x + 2 - 3x + 5
  3. Combine like terms (x):               8x² - 7x + 2 + 5
  4. Combine like terms (Z):              8x² - 7x + 7
8 0
3 years ago
Which equation has the solutions x=1+or-square root of 5?
stiv31 [10]

We will proceed to solve each case to determine the solution of the problem.

<u>case a)</u> x^{2}+2x+4=0

Group terms that contain the same variable, and move the constant to the opposite side of the equation

x^{2}+2x=-4

Complete the square. Remember to balance the equation by adding the same constants to each side.

x^{2}+2x+1=-4+1

x^{2}+2x+1=-3

Rewrite as perfect squares

(x+1)^{2}=-3

(x+1)=(+/-)\sqrt{-3}\\(x+1)=(+/-)\sqrt{3}i\\x=-1(+/-)\sqrt{3}i

therefore

case a) is not the solution of the problem

<u>case b)</u> x^{2}-2x+4=0

Group terms that contain the same variable, and move the constant to the opposite side of the equation

x^{2}-2x=-4

Complete the square. Remember to balance the equation by adding the same constants to each side.

x^{2}-2x+1=-4+1

x^{2}-2x+1=-3

Rewrite as perfect squares

(x-1)^{2}=-3

(x-1)=(+/-)\sqrt{-3}\\(x-1)=(+/-)\sqrt{3}i\\x=1(+/-)\sqrt{3}i

therefore

case b) is not the solution of the problem

<u>case c)</u> x^{2}+2x-4=0

Group terms that contain the same variable, and move the constant to the opposite side of the equation

x^{2}+2x=4

Complete the square. Remember to balance the equation by adding the same constants to each side.

x^{2}+2x+1=4+1

x^{2}+2x+1=5

Rewrite as perfect squares

(x+1)^{2}=5

(x+1)=(+/-)\sqrt{5}\\x=-1(+/-)\sqrt{5}

therefore

case c) is not the solution of the problem

<u>case d)</u> x^{2}-2x-4=0

Group terms that contain the same variable, and move the constant to the opposite side of the equation

x^{2}-2x=4

Complete the square. Remember to balance the equation by adding the same constants to each side.

x^{2}-2x+1=4+1

x^{2}-2x+1=5

Rewrite as perfect squares

(x-1)^{2}=5

(x-1)=(+/-)\sqrt{5}\\x=1(+/-)\sqrt{5}

therefore

case d) is the solution of the problem

therefore

<u>the answer is</u>

x^{2}-2x-4=0

5 0
3 years ago
Read 2 more answers
Someone help me please! I don’t understand this.
trasher [3.6K]
All you have to do is multiply them!make sure to turn them into improper drafting before tho!
5 0
3 years ago
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