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NNADVOKAT [17]
3 years ago
12

Help me please with this question ​

Mathematics
1 answer:
Elena-2011 [213]3 years ago
6 0

Answer:

second option

Step-by-step explanation:

Given

A = 4xy ( to isolate x divide both sides by 4y )

\frac{A}{4y} = x , that is x = \frac{A}{4y}

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(PLEASE IM DESPERATE) 3. A toy catapult launched a ball. The height of the ball could be modelled by
Elena-2011 [213]

Answer:

I think it could be modelled by the function I'm  not 100 percent sure but i hope it helps

Step-by-step explanation:

8 0
3 years ago
Please help<br> See the picture <br> Twst
erik [133]

Answer:

7

Step-by-step explanation:

1. Use sine law to solve

3/sin35 = x/sin55

3sin55/sin35 = 7

6 0
2 years ago
What is the image of (1,0) after a counterclockwise rotation of 60 degrees?
Anestetic [448]

Answer:

\vec s = \left(\frac{1}{2},\frac{\sqrt{3}}{2}  \right)

Step-by-step explanation:

The coordinate has the following polar form:

\vec r = (1, 0^{\circ})

The image of the coordinate rotated counterclockwise 60° is:

\vec s = (1, 60^{\circ})

Its equivalent form in rectangular coordinates is:

\vec s = (1\cdot \cos 60^{\circ}, 1 \cdot \sin 60^{\circ})

\vec s = \left(\frac{1}{2},\frac{\sqrt{3}}{2}  \right)

3 0
2 years ago
Juan is making a model out of rhombi. Each rhombus will be connected to the one before it. Each rhombus will be 6 inches tall an
love history [14]

He will need 12 sq. inches of Paper for each rhombus.

Given: 6 inches tall and 4 inches wide.

so, Length of the diagonals are 6 and 4 inches respectively.

Refer to figure.

The two diagonals cuts the rhombus into four equal parts, so

Area of one rhombus = 4 x (area of 1 part of the rhombus)

Now,

Area of 1 part of the rhombus = \frac{1}{2} x 3 x 2

                                                  = 3 sq. inches

Area of one rhombus = 4 x 3 = 12 sq. inches

Hence, 12 sq. inches of Paper is needed for each rhombus.

Learn more about the "Finding the area of the rhombus" Here : brainly.com/question/10684261

#SPJ4

5 0
1 year ago
Read 2 more answers
Greatest to least<br> 2/7, 1/4, 2/9
Stella [2.4K]

<u>1/3; 2/7; 2/9</u>

Lets find least common multiple

The least common multiple is 63

1/3 --> 21/63

2/7 --> 18/63

2/9 --> 14/63

As you can see I am correct, but I found the LCM by multiplying 1/3 by 21 to get to 63 and the numerator as well

7 0
3 years ago
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