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s2008m [1.1K]
3 years ago
9

Which statement about the population shown in this graph is true? A. The number of individuals will increase endlessly. B. The n

umber of individuals will eventually drop to zero. C. The population has increased until it reached its carrying capacity. D. There are no limiting factors to control population growth.
Mathematics
2 answers:
Mandarinka [93]3 years ago
8 0
Hello


D will be your correct answer.

Hope this helps 
bearhunter [10]3 years ago
5 0
D is the answer to this question
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Analyze the diagram below and complete the instructions that follow. / Find the value of x. A. 4 B. 5 C. 6 D. 9
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Answer:

C

Step-by-step explanation:

x^2 + (x+3)^2 = 117

x^2 + x^2+6x+9 =117

2x^2 + 6x - 108 = 0

(2x-12)(x+9)=0

x=-9,6

x cannot be negative therefore, x = 6

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Thirty work orders are selected from a filing cabinet containing 500 work order folders by choosing every 15th folder. which sam
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A certain substance doubles its volume every minute at 9 AM a small amount is placed in a container ,at 10 AM the container was
Y_Kistochka [10]

Answer:

the container is 1/4 full at 9:58 AM

Step-by-step explanation:

since the volume doubles every minute , the formula for calculating the volume V at any time t is

V(t)=V₀*2^-t , where t is in minutes back from 10 AM and V₀= container volume

thus for t=1 min (9:59 AM) the volume is V₁=V₀/2 (half of the initial one) , for t=2 (9:58 AM) is V₂=V₁/2=V₀/4  ...

therefore when the container is 1/4 full the volume is V=V₀/4 , thus replacing in the equation we obtain

V=V₀*2^-t

V₀/4 = V₀*2^-t

1/4 = 2^-t

appling logarithms

ln (1/4) = -t* ln 2

t = - ln (1/4)/ln 2 = ln 4 /ln 2 = 2*ln 2 / ln 2 = 2

thus t=2 min before 10 AM → 9:58 AM

therefore the container is 1/4 full at 9:58 AM

8 0
3 years ago
Which of the following is a point-slope equation for a line with the point (-2,4) and a slope of 3?
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work is shown and pictured

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The first three terms of a sequence are given. Round to the nearest thousandth (if necessary). 152,149,146
Serhud [2]

Answer:

the 30th term is 239

Step-by-step explanation:

The computation of the 30th term is as follows:

As we know that

a_n = a_1 + (n-1)d

where

a_1 is the first number is the sequence

n = the term

And, d = common difference

Now based on this, the 30th term is

= 152 + (30 - 1) × 3

= 152 + 29 × 3

= 152 + 87

= 239

Hence, the 30th term is 239

7 0
3 years ago
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