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GuDViN [60]
3 years ago
10

A catalog sales company promises to deliver orders placed on the Internet within 3 days.​ Follow-up calls to a few randomly sele

cted customers show that a​ 95% confidence interval for the proportion of all orders that arrive on time is 70​%±88​%.
A. What does this​ mean? For each​ conclusion, state whether it is correct or not and explain why. Complete parts a through e below. ​
B. Between 62​% and 78​% of all orders arrive on time. State whether the conclusion is correct or not and explain why. Choose the correct answer below.
Mathematics
1 answer:
Tju [1.3M]3 years ago
3 0

Answer:B. Between 62​% and 78​% of all orders arrive on time. State whether the conclusion is correct or not and explain why. Choose the correct answer below.

Step-by-step explanation:

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Write the equation y=-1/2x+3 in standard form. how do I do this?
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Please help if you can thanks ^^
Neko [114]

Given:

AD is an angle bisector in triangle ABC. m\angle CAB=44^\circ, m\angle ACB=72^\circ, m\angle ABC=64^\circ.

To find:

The value of m\angle ADC.

Solution:

AD is an angle bisector in triangle ABC.

m\angle CAD=m\angle BAD=\dfrac{m\angle CAB}{2}

m\angle CAD=m\angle BAD=\dfrac{44^\circ}{2}

m\angle CAD=m\angle BAD=22^\circ

According to the angle sum property, the sum of all interior angles of a triangle is 180 degrees.

Using angle sum property in triangle CAD, we get

m\angle CAD+m\angle ADC+m\angle ACB=180^\circ

22^\circ+m\angle ADC+72^\circ=180^\circ

m\angle ADC+94^\circ=180^\circ

m\angle ADC=180^\circ-94^\circ

m\angle ADC=86^\circ

Therefore, the angle of angle ADC is 86^\circ.

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3 years ago
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3 years ago
A student wants to determine the coefficients of static friction and kinetic friction between a box and a plank. She places the
Arturiano [62]

Answer:

the coefficients of static friction is 0.577

the coefficients of fkinetic friction is 0.54

Step-by-step explanation:

given information

θ = 30°

S = 2.5 m

t = 4 s

- Static friction

F - F(friction) = 0

W sin θ = μs W cos θ  

μs = sin θ/ cosθ

   = tan θ

   = tan 30°

   = 0.577

- kinetic friction

S = v_{0} t + \frac{1}{2} at^{2}

v_{0} t = 0

S = \frac{1}{2} at^{2}

a = \frac{2S}{T^{2} } = \frac{2 x 2.5}{4^{2} }

  = 0.3 m/s^{2}

F - F(friction) = m a

W sin θ - μ W cos θ  = m a

mg sin θ - μk mg cos θ  = m a

g sin θ - μk g cos θ  = a

μk = g sin θ  - a / g cos θ

    = 9.8 sin 30° - 0.3 / 9.8 cos 30°

    = 0.54

7 0
4 years ago
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