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1 year ago

HELP......................................

Mathematics

1 answer:

djyliett [7]1 year ago

4 0

Answer:

The equation's result: 32,000 (Rounded)

Goal: Find the closest or equivalent result in another expression

Step-by-step explanation:

$(1.5^{15})/(0.7^{12})\\(1.5^{15})/(0.7^{12}) = (437.894)/(0.7^{12})\\437.894/(0.014)\\31636.79$

How we got to 31,636 was by dividing from left to right.

Remember: When dividing decimals, it's like multiplying whole numbers in a way. The number(the quotient, also) ends up bigger instead of being smaller like when dividing whole numbers. If you multiply decimals, they(the product) end up smaller.

Therefore, A is the correct answer.

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Maria's book is longer than Brandon's. The difference in the two book lengths is 56

Bingel [31]

Answer:

Maria's book is 202 pages long, Brandon's book is 146 pages long

Step-by-step explanation:

We can set this up with 2 variables: lets say that Maria's book length is x and Brandon's is y.

We can see that Maria's book is 56 pages longer than Brandon's and can come up with an equation:

x=y+56

We also see that their booklengths add up to 348, and can get:

x+y=348

From here, we solve for x and y. We can use substitution to find y.

x+y=348

(y+56)+y=348

2y=292

y=146

Here we plug in for x:

x=y+56

x=(146)+56

x=202

Therefor we get that Maria's book is 202 pages long, Brandon's book is 146 pages long

7 0

2 years ago

A quality assurance engineer randomly checks manufactured parts to ensure that they are within 0.002 mm of the desired specifica

Neko [114]

|x - 3| ≤ 0.002 your answer should be A

4 0

3 years ago

Read 2 more answers

104/35 divided by 3/2 as a fraction

Ratling [72]

Answer:

1 and 103/105

Step-by-step explanation:

3 0

3 years ago

The coordinate plane below represents a city.

alex41 [277]

Answer:

Part A) The system of inequalities is

$x\geq2$ and $y\geq2$

Part B) In the procedure

Part C) The schools that Natalie is allowed to attend are A,B and D

Step-by-step explanation:

Part A: Using the graph above, create a system of inequalities that only contain points C and F in the overlapping shaded regions

we have

Points C(2,2), F(3,4)

The system of inequalities could be

$x\geq2$ -----> inequality A

The solution of the inequality A is the shaded area at the right of the solid line x=2

$y\geq2$ -----> inequality B

The solution of the inequality B is the shaded area above of the solid line y=2

see the attached figure N 1

Part B: Explain how to verify that the points C and F are solutions to the system of inequalities created in Part A

we know that

If a ordered pair is a solution of the system of inequalities, then the ordered pair must satisfy both inequalities

Verify point C

C(2,2)

<em>Inequality A</em>

$x\geq2$ -----> $2\geq2$ ----> is true

<em>Inequality B</em>

$y\geq2$ ------> $2\geq2$ ----> is true

therefore

Point C is a solution of the system of inequalities

Verify point D

F(3,4)

Inequality A

$x\geq2$ -----> $3\geq2$ ----> is true

Inequality B

$y\geq2$ ------> $4\geq2$ ----> is true

therefore

Point D is a solution of the system of inequalities

Part C: Natalie can only attend a school in her designated zone. Natalie's zone is defined by y < −2x + 2. Explain how you can identify the schools that Natalie is allowed to attend.

we have

$y < -2x+2$

The solution of the inequality is the shaded area below the dotted line $y=-2x+2$

The y-intercept of the dotted line is the point (0,2)

The x-intercept of the dotted line is the point (1,0)

To graph the inequality, plot the intercepts and shade the area below the dotted line

see the attached figure N 2

therefore

The schools that Natalie is allowed to attend are A,B and D

6 0

4 years ago

<img src="https://tex.z-dn.net/?f=f%28x%29%3D%281-0.08%29%5E%7B%5Cfrac%7B1%7D%7B12%7D%20%7D%20%5E%7B%2812t%29%7D" id="TexFormula

oksano4ka [1.4K]

Answer:

See Below.

Step-by-step explanation:

We have:

$\displaystyle f(x)=(1-0.08)^{\frac{1}{12}(12t)}$

First, we can subtract within the parentheses:

$f(x)=(0.92)^{\frac{1}{12}(12t)}$

By the properties of exponents:

$f(x)=((0.92)^\frac{1}{12})^{12t}$

Approximate. Use a calculator:

$f(x)\approx (0.993)^{12t}$

Notes:

0.993 is only an approximation, hence the approximately equal sign.

I'm not given the context of the problem, but it's simpler to just simplify in the exponent like so (the fractions cancel):

$\displaystyle f(x)=(1-0.08)^{\frac{1}{12}(12t)}=(0.92)^t$

Full Problem:

The value of Sara's car decreases at a rate of 8% per year.

We will use the exponential decay formula with a set time, given by:

$f(x)=a(r)^{x/d}$

Where a is the initial value, r is the rate, x is the time that has passed (dependent on d), and d is the amount of time for one decrease.

For this problem, we can ignore the initial value.

And since the value decreases at a rate of 8% per year, r = 0.92 (we acquire this from 1 - 0.08).

Part 1) Per Month:

Since it decreases per month, d = 12.

$f(x)=(0.92)^{x/12}$

Approximate:

$f(x)=((0.92)^{1/12})^x\approx(.993)^x$

In this case, x is measured in months.

Part 2) Per Week:

Since it decreases per week, d = 52.

$f(x)=(0.92)^{x/52}$

Approximate:

$f(x)=((0.92)^1/52)^x\approx (.998)^x$

In this case, x is measured in weeks.

Part 3) Per Day:

So, d = 365.

$f(x)=(0.92)^{x/365}$

Simplify:

$f(x)=((0.92)^{1/365})^x\approx(.999)^x$

In this case, x is measured in days.

Part 4)

So, as d increases, our r increases as well.

Therefore, the smaller the time interval (from months to weeks to days), the higher our rate of decrease is.

8 0

3 years ago