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Greeley [361]
1 year ago
7

HELP......................................

Mathematics
1 answer:
djyliett [7]1 year ago
4 0

Answer:

The equation's result: 32,000 (Rounded)

Goal: Find the closest or equivalent result in another expression

Step-by-step explanation:

<h3>A)</h3>

(1.5^{15})/(0.7^{12})\\(1.5^{15})/(0.7^{12}) = (437.894)/(0.7^{12})\\437.894/(0.014)\\31636.79

How we got to 31,636 was by dividing from left to right.

Remember: When dividing decimals, it's like multiplying whole numbers in a way. The number(the quotient, also) ends up bigger instead of being smaller like when dividing whole numbers. If you multiply decimals, they(the product) end up smaller.

Therefore, A is the correct answer.

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How many are 10 x 10 ?​
Hunter-Best [27]

Answer:

100

Step-by-step explanation:

Count to ten ten times and you'll get 100

4 0
3 years ago
50 POINTS!!! HELP!!! What is the answer?
kobusy [5.1K]
Isn't this the NWEA?
3 0
3 years ago
Read 2 more answers
The National Transportation Safety Board publishes statistics on the number of automobile crashes that people in various age gro
ra1l [238]

Answer:

a) Null hypothesis:p\leq 0.12  

Alternative hypothesis:p > 0.12  

b) z_{\alpha}=1.64

c) z=\frac{0.134 -0.12}{\sqrt{\frac{0.12(1-0.12)}{1000}}}=1.362  

d) p_v =P(z>1.362)=0.0866  

e) For this case since the statistic is lower than the critical value and the p value higher than the significance level we have enough evidence to FAIL to reject the null hypothesis so then we don't have information to conclude that the true proportion is higher than 0.12

Step-by-step explanation:

Information given

n=1000 represent the random sample selected

X=134 represent the number of young drivers ages 18 – 24 that had an accident

\hat p=\frac{134}{1000}=0.134 estimated proportion of young drivers ages 18 – 24 that had an accident

p_o=0.12 is the value that we want to verify

\alpha=0.05 represent the significance level

Confidence=95% or 0.95

z would represent the statistic

p_v{/tex} represent the p valuePart aWe want to verify if the population proportion of young drivers, ages 18 – 24, having accidents is greater than 12%:  Null hypothesis:[tex]p\leq 0.12  

Alternative hypothesis:p > 0.12  

The statistic would be given by:

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

Part b

For this case since we are conducting a right tailed test we need to find a critical value in the normal standard distribution who accumulates 0.05 of the area in the right and we got:

z_{\alpha}=1.64

Part c

For this case the statistic would be given by:

z=\frac{0.134 -0.12}{\sqrt{\frac{0.12(1-0.12)}{1000}}}=1.362  

Part d

The p value can be calculated with the following probability:

p_v =P(z>1.362)=0.0866  

Part e

For this case since the statistic is lower than the critical value and the p value higher than the significance level we have enough evidence to FAIL to reject the null hypothesis so then we don't have information to conclude that the true proportion is higher than 0.12

8 0
3 years ago
A serving of chickenpeas contain 1,750 milligrams of potassium. how many grams of potassium is that
Sidana [21]

1.75 Grams is what I got. Every 1 Milligram = 0.001 Gram.

Hope it helps :)


8 0
3 years ago
Dennis and Connie purchased a radio for $128. Dennis paid $36 more than Connie. How much did each pay?
never [62]

Answer:

Dennis paid $82 and Connie paid $46.

Step-by-step explanation:

We can set up an equation by putting in variables, c representing how much Connie paid. Since we know that Dennis paid $36 more, we will also factor that in the equation.

c + c + 36 = 128

Where c + 36 represents the amount Dennis paid, and 128 represents the total amount paid as given in the question. We can start by adding like terms. 2c + 36 = 128

Now, we can subtract 36 from each side,

2c + 36 - 36 = 128 - 36

2c = 92

Divide each side by two,

2c/2 = 92/2

c = 46

Now, to make sure this is correct, let's substitute our c for 46 in our equation:

46 + 46 + 36 = 128

92 + 36 = 128

128 = 128

Therefore, our equation is correct, and Dennis paid $82 while Connie paid $46.

6 0
3 years ago
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