3 years ago

A) 2x+3>11 Faceti rezolvarea varog

Mathematics

1 answer:

Vladimir79 [104]3 years ago

8 0

2(6)+3>11, is the answer

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quester [9]

Question a

g(x) times $\sqrt{x-5}=\sqrt{x^2-5}$
divide both sides by √(x-5)
$g(x)=\frac{\sqrt{x^2-5}}{\sqrt{x-5}}$
$g(x)=\frac{(\sqrt{x-5})(\sqrt{x^2-5})}{x-5}$
$g(x)=\frac{\sqrt{x^3-5x^2-5x+25}}{x-5}$

question b
$g(x) \space\ times \space\ 1+\frac{1}{x}=x$
divide both sides by 1+1/x
$g(x)=\frac{x}{1+\frac{1}{x}}$
times by x/x
$g(x)=\frac{x^2}{x+1}$

question c
$\frac{1}{x} \space\ times \space\ f(x)=x$
times both sides by x
$f(x)=x^2$

question d
the (f*g)(x) collumn seems to have a domain of only x is greater than or equal to 0?
so maybe we squared the whole thing, ya
wait
ah, ya
basically
$|x|=(\sqrt{x})^2=(\sqrt{x})(\sqrt{x})$
so f(x)=√x

a. $g(x)=\frac{\sqrt{x^3-5x^2-5x+25}}{x-5}$
b. $g(x)=\frac{x^2}{x+1}$
c. $f(x)=x^2$
d. $f(x)=\sqrt{x}$

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