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2 years ago

If m angle 2 = x+8 and m angle 3 =2x+7 ,what is m angle 2?

Mathematics

1 answer:

n200080 [17]2 years ago

8 0

Answer: 25

Step-by-step explanation:

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Ten times the quotient of 104 and 8

GREYUIT [131]

104 ÷ 8 = 13
13 x 10 = 130
Answer: 130

If you need information about the quotient, it is the answer to 2 numbers divided together. For example, the quotient of 999 and 111 is 9, because 999 ÷111 =9

5 0

2 years ago

Read 2 more answers

Can someone please tell me how to solve this?: -27 , exponent 2/3 -27^2/3

Vlada [557]

So this is asking the cube root of -27 then squared.
Cube root of -27=-3
And -3^2=9

So I believe your answer is 9

4 0

2 years ago

To the nearest whole degree, what angle measure has a sine of 0.3535? SOMEBODY HELP

Bas_tet [7]

The angle is sin inverse 0.3535 which is around 21 degrees

5 0

2 years ago

Help me pls i give brainliest

Yakvenalex [24]

Answer:

away from the origin at a decreasing velocity

Step-by-step explanation:

I think this is right.

I hope this helps! (✿◕‿◕✿)

7 0

2 years ago

Determine the domain of the function (fog)(x) where f(x)=3x-1/x-4 and g(x)=x+1/x

Katarina [22]

Answer: (-∞,-1) ∪ (0,+∞)

Step-by-step explanation: The representation fog(x) is a representation of composite function, meaning one depends on the other.

In this case, fog(x) means:

fog(x) = f(g(x))

fog(x) = $3(x+\frac{1}{x} )-\frac{1}{x+\frac{1}{x} } -4$

$fog(x)=3x+\frac{3}{x} -\frac{1}{\frac{x^{2}+x}{x} } -4$

$fog(x)=3x+\frac{3}{x} -\frac{x}{x^{2}+x} -4$

$fog(x)=\frac{3x^{2}(x^{2}+x)+3(x^{2}+x)-x-4x(x^{2}+x)}{x(x^{2}+x)}$

$fog(x)=\frac{3x^{4}+3x^{3}+3x^{2}+3x-x-4x^{3}+4x^{2}}{x(x^{2}+x)}$

$fog(x)=\frac{3x^{4}-x^{3}-x^{2}+2x}{x(x^{2}+x)}$

This is the function fog(x).

The domain of a function is all the values the independent variable can assume.

For fog(x), denominator can be zero, so:

$x(x^{2}+x) \neq 0$

If x = 0, the function doesn't exist.

$x^{2}+x \neq0$

$x(x+1) \neq0$

$x+1\neq0$

$x\neq-1$

Therefore, the domain of this function is: -∞ < -1 or x > 0

5 0

2 years ago