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Alona [7]
3 years ago
13

Find the unknown side length, x. Write your answer in simplest radical form.

Mathematics
1 answer:
Luda [366]3 years ago
3 0

Answer:

√41

Step-by-step explanation:

Considering the sides with lengths 48 and 52 units, we would use Pythagoras theorem to find the third side. Let that side be t

52² = 48² + t²

t² = 52² - 48²

= 2704 - 2304

= 400

t = √400

= 20

Considering the next triangle with sides t (20 units) and 12 units, again using the theorem

20² = 12² + y²

where y is the third side

400 = 144 + y²

y² = 400 - 144

= 256

y = √256

= 16 units

Considering the triangle with two sides given as 5 and 13 units, the third side (which is part of the 16 units calculated earlier)

13² = 5² + u²

where u is the 3rd side

169 = 25 + u²

u² = 169 - 25

u² = 144

u = √144

u = 12

The other part of the side of that triangle

= 16 - 12

= 4

Considering the smallest triangle whose sides are x, 5 and 4,

x² = 5² + 4²

= 25 + 16

= 41

x = √41

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Answer:

17 m² or 17 square meters

Step-by-step explanation:

A trapezoid has base lengths of 5 meters and 3.5 meters. If the height of the trapezoid is 4 meters, what is the area of the trapezoid?

Area of a trapezoid =1/2(b1 + b2)h

Where

b1 = First base length = 5m

b2 = Second base length = 3.5 m

Height = 4m

= 1/2(5m + 3.5m) × 4m

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= 1/2 × 8.5m × 4m

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Therefore, the area of the trapezoid is 17 m² or 17 square meters

6 0
3 years ago
An urn contains ten chips. An unknown number of chips are white' the others are red. We wish to test:
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Answer:

Let’s denote X to be the number of white chips in the sample and E be the event that exactly half of the chips  are white. Then,

a) Find α

α = P (reject H0 | H0 is true) = P (X ≥ 2|E)  

  = P (X = 2|E) + P (X = 3|E),    

We took two case, as we can draw only only three chips with two or more white to reject H0, it means we can only take 2 white chips or 3, not more, we get solution

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So,  α = 0.5

b) Find β

i) Let E1 be the event that the urn contains 6 white and 4 red chips. (As given)

β = P (accept H0 | E1) = P (X ≤ 1|E1)

  =  (6C0 * 4C3)/10C3  +  (6C1 * 4C2)/10C3

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So, β = 0.333

i) Let E2 be the event that the urn contains 7 white and 3 red chips. (As given)

β = P (accept H0 | E2) = P (X ≤ 1|E2)

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So, β = 0.183

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4 years ago
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Answer:

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Step-by-step explanation:

EGEN 2021, got it right on practice

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