Question

Can somebody help me?

Answer 1

Answer:

See explanation

Step-by-step explanation:

The given function is $f(x)=-(x+2)^2-1$

You could observe that: $a=-1$ when you compare to $f(x)=a(x+h)^2+k$.

This should tell you that the graph should open downwards.

Let us substitute $x=3$, to get: $f(2)=-(3+2)^2-1=-5^2-1=-26$

Also when x=4,$f(4)=-(4+2)^2-1=-6^2-1=-36-1=-37$

All the results are negative so the graph should appear below the x-axis

This shows that AJ made a mistake in the graph.