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zvonat [6]
3 years ago
5

Evaluate the given function for the given value. f(x)=floor(x)​; x=−1.2

Mathematics
1 answer:
Iteru [2.4K]3 years ago
6 0

Answer:

x=12x=floor

Step-by-step explanation:

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Solve the following system of equations by elimination. What is the value of x? x = 1.5 x = -1.5 x = 8 x = -8
Andru [333]

Using the elimination method, the value of x in the system of equations is calculated as: 8.

<h3>How to Solve a System of Equations by Elimination?</h3>

To solve a system of equations given using the elimination method, do the following:

Multiply 2x - 5y = 1 by 2 and multiply -3x + 2y = -18 by 5 to get the following:

4x - 10y = 2 --> eqn. 1

-15x + 10y = -90 --> eqn. 2

Add

-11x = -88

Divide both sides by -11

x = 8

Learn more about system of equations on:

brainly.com/question/14323743

#SPJ1

8 0
2 years ago
If a person invests $500 at 2% simple interest for 4 years how much interest is earned
irinina [24]
$40
500×2% is 10×4 is 40
6 0
3 years ago
Is (1, 2) a solution to this system of equations? 10x + 4y = 18 x + 9y = 19
Arlecino [84]

Answer:

Yes

Step-by-step explanation:

The intersection point of 10x+4y=18 and x+9y=19 is (1,2) on a graph.

3 0
3 years ago
Find the volume in cubic meter (C.U.M) of each of the cuboid whose dimensions are :
Leno4ka [110]

The volume in cubic meter of the cuboid with the dimensions length = 12 m , breadth = 10m, height = 4.5 m is 540 m³

<h3 />

<h3>Volume of a cuboid:</h3>
  • v = lwh

where

l =- length

w = width

h = height

Therefore,

l = 12 m

w = 10 m

h = 4.5

v = 12 × 10 × 4.5

v = 120 × 4.5

v = 540 m³

learn more on cuboid here: brainly.com/question/14297267?referrer=searchResults

7 0
2 years ago
Read 2 more answers
The Magazine Mass Marketing Company has received 10 entries in its latest sweepstakes. They know that the probability of receivi
Serjik [45]

Answer:

P(X>4)= 0.624

Step-by-step explanation:

Given that

n = 10

p= 0.5 ,q= 1 - p = 0.5

Two fifth of 10 = 2/5 x 10 =4

It means that we have to find probability P(X>4).

P(X>4)= 1 -P(X=0)-P(X=1)-P(X=2)-P(X=3)-P(X=4)

We know that

P(X=x)=(_{x}^{n})\ p^xq^{n-x}

P(X=0)=(_{0}^{10})\ 0.5^0\ 0.5^{10}=0.0009

P(X=1)=(_{1}^{10})\ 0.5^1\ 0.5^{9}=0.0097

P(X=2)=(_{2}^{10})\ 0.5^2\ 0.5^{8}=0.043

P(X=3)=(_{3}^{10})\ 0.5^3\ 0.5^{7}=0.117  

P(X=4)=(_{4}^{10})\ 0.5^3\ 0.5^{7}=0.205

P(X>4)= 1 -P(X=0)-P(X=1)-P(X=2)-P(X=3)-P(X=4)

P(X>4)= 1 -0.0009 - 0.0097 - 0.043 - 0.117-0.205

P(X>4)= 0.624

8 0
3 years ago
Read 2 more answers
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