Solve. 3/ k+3 = 8/ k-2 A.) k= -1 B.) k= 1 C.) k= -6 D.) k= 6

1 answer:

6 0

3/k+3=8/k-2
butterfly (multiply 8 and k+3) and (multiply 3 and k-2) and set them = to eachother
8 (k+3)=3 (k-2)
distribute
8k+24=3k-6
-3k both sides
5k+24=-6
-24 both sides
5k=-30
÷5 both sides
k=-6

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How should I do this question

Ivanshal [37]

Answer:

( 11 -6)

( -5 6 )

Step-by-step explanation:

Multiply the first row of N by first column of M. This will give the first element in top row of the answer :-

-3*-2 + 1*5 = 11

Then multiply the first row in N by the second column of M to give the second element of the top row.

-3*0 + 1*-6 = -6

Then do a similar process with the second row in N.

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3 years ago

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Show that every triangle formed by the coordinate axes and a tangent line to y = 1/x ( for x > 0)

vfiekz [6]

Answer:

Step-by-step explanation:

given a point $(x_0,y_0)$ the equation of a line with slope m that passes through the given point is

$y-y_0 = m(x-x_0)$ or equivalently

$y = mx+(y_0-mx_0)$ .

Recall that a line of the form $y=mx+b$ , the y intercept is b and the x intercept is $\frac{-b}{m}$ .

So, in our case, the y intercept is $(y_0-mx_0)$ and the x intercept is $\frac{mx_0-y_0}{m}$ .

In our case, we know that the line is tangent to the graph of 1/x. So consider a point over the graph $(x_0,\frac{1}{x_0})$ . Which means that $y_0=\frac{1}{x_0}$