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Anvisha [2.4K]
3 years ago
5

Austin wants to make twelve gallons of 46% acid solution by mixing together 65% acid solution and a

Mathematics
1 answer:
jarptica [38.1K]3 years ago
4 0

Answer:

Austin should use 8.2 gallons of 65% acid solution and 3.8 gallons 5% acid solution

Step-by-step explanation:

Let

x ----> the gallons of 65% acid solution needed

y ----> the gallons of 5% acid solution needed

Remember that

46\%=46/100=0.46

65\%=65/100=0.65

5\%=5/100=0.05

we know that

x+y=12 -----> equation A

0.65x+0.05y=0.46(12) -----> equation B

Solve the system by graphing

The solution is the intersection point both graphs

using a graphing tool

The solution is (8.2,3.8)

therefore

Austin should use 8.2 gallons of 65% acid solution and 3.8 gallons 5% acid solution

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Based on the Nielsen ratings, the local CBS affiliate claims its 11:00 PM newscast reaches 41 % of the viewing audience in the a
ZanzabumX [31]

Answer:

1) Null hypothesis:p\geq 0.41  

Alternative hypothesis:p < 0.41

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And we can use the following excel code to find it: "=NORM.INV(0.01,0,1)"

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And we can use the following excel code to find it: "=NORM.INV(0.1,0,1)"

6) We see that |t_{calculated}| so then we have enough evidence to FAIL to reject the null hypothesis at 1% of significance.

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Step-by-step explanation:

Data given and notation  

n=100 represent the random sample taken

X represent the people indicated that they watch the late evening news on this local CBS station

\hat p=0.36 estimated proportion of people indicated that they watch the late evening news on this local CBS station

p_o=0.41 is the value that we want to test

\alpha=0.05 represent the significance level

Confidence=95% or 0.95

z would represent the statistic (variable of interest)

p_v{/tex} represent the p value (variable of interest)  Part 1We need to conduct a hypothesis in order to test the claim that 11:00 PM newscast reaches 41 % of the viewing audience in the area:  Null hypothesis:[tex]p\geq 0.41  

Alternative hypothesis:p < 0.41

Part 2  

\hat p=0.36 estimated proportion of people indicated that they watch the late evening news on this local CBS station

Part 3

Since we have a left tailed test we need to see in the normal standard distribution a value that accumulates 0.01 of the area on the left and on this case this value is :

z_{crit}=-2.33

And we can use the following excel code to find it: "=NORM.INV(0.01,0,1)"

Part 4

When we conduct a proportion test we need to use the z statisitc, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

Since we have all the info requires we can replace in formula (1) like this:  

z=\frac{0.36 -0.41}{\sqrt{\frac{0.41(1-0.41)}{1000}}}=-1.017  

Part 5

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Part 6

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Part 7

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