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Nesterboy [21]
3 years ago
8

PLEASE HELP ME CAN YOU PLEASE TELL Me WHAT RATIO MEANES IN 3 WAYS!!!! PLS NOT FROM WIKAPIDIA PLS

Mathematics
1 answer:
Anna35 [415]3 years ago
6 0
Ratio means only one thing but I think what you meant was 3 examples of a ratio. In that case three examples would be: 2:3, 2 to 3, 2/3
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Line JK bisects line LM at point J. Find JM if LJ=23 centimeters
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Ling JM is also 23 centimeters because line LJ and JM are a line but broken into two segments
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Which graph represents a function with an initial value of One-half?
sweet [91]

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The answer is B

Step-by-step explanation:

I went on socratic and found the answer

7 0
3 years ago
Ayana has 220 coins in her piggy bank Of those 40percent are pennies. Out of the coins that are not pennies 25 percent are partn
Rzqust [24]
To find a percent of a number, multiply the percent by the number.

First we find the number of pennies.

40% of 220 =

= 40% * 220

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3 0
3 years ago
F(x)=(x+4) 2 −25<br><br> smaller x =<br><br> larger x = <br><br> NEED THIS ASAP
miss Akunina [59]

f(x)=(x+4) ^2 −25

to solve set equal to zero

0 =(x+4) ^2 −25

add 25 to each side

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take the square root of each side

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+- 5 = (x+4)

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3 0
3 years ago
Please hepl with math
Ivenika [448]

Answer:

\dfrac{5^{n+2}-6\times 5^{n+1}}{13 \times5^{n}-2\times5^{n+1}} = -\dfrac{5}{3}

Step-by-step explanation:

We are given the expression to be simplified:

\dfrac{5^{n+2}-6\times 5^{n+1}}{13 \times5^{n}-2\times5^{n+1}}

Let us take common a term with a power of 5 from the numerator and the denominator of the given expression.

We know that:

a^{p+q} = a^p \times a^q

Let us use it to solve the powers of 5 in the given expression.

\therefore we can write:

5^{n+2} = 5^{n+1}\times 5= 5^n\times 5^{2}

5^{n+1} = 5^n\times 5

The given expression becomes:

\dfrac{5^{n+1} \times 5-6\times 5^{n+1}}{13 \times5^{n}-2\times5^{n}\times 5}

Taking common 5^{n+1} from the numerator and

Taking common 5^{n} from the denominator

\Rightarrow \dfrac{5^{n+1} (5-6)} {5^{n}(13-2\times5)}\\\Rightarrow \dfrac{5^{n+1} (-1)} {5^{n}(13-10)}\\\Rightarrow -\dfrac{5^{n+1}} {5^{n}\times3}\\\Rightarrow -\dfrac{5^{n}\times 5} {5^{n}\times3}\\\Rightarrow -\dfrac{5}{3}

\therefore The answer is:

\dfrac{5^{n+2}-6\times 5^{n+1}}{13 \times5^{n}-2\times5^{n+1}} = -\dfrac{5}{3}

6 0
3 years ago
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