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2 years ago

Sammi bought 2dozen valentines. How many valentines did sammi have left after giving 7/8 of them to her classmates

Mathematics

1 answer:

Ierofanga [76]2 years ago

8 0

Dozen = 12

2 dozen

2x12=24

7/8 of 24

24 / 8 = 3
3 x 7 = 21
24- 21= 3

3 roses are left over

Top question: -7°

Bottom question : 18°

Step-by-step explanation:

Top question:

The base angles of am isosceles triangle are congruent:

x + 46 = 39 because the base angles of an isosceles triangle are congruent

x + 46° = 39°

x = -7°

Bottom question

The missing angle is 3x because the base angles are congruent

To find the value of x, we must add all the angles inside the triangle, and find the value of x that makes it equal to 180°

3x + 3x + 4x = 180°

10x = 180°

x = 18°

Sorry for the late post!

-Chetan K

8 0

2 years ago

Factorise and divide 3^ 2 (2 ^2 − 14 + 24) ÷ 6 ( x − 4)

Fiesta28 [93]

Answer:

i think its 21/x-4

Step-by-step explanation:

sorry if im wrong

3 0

1 year ago

What is the equivalent ratio to 8:1 and :7

topjm [15]

Answer: 56:7

Step-by-step explanation:

You would do 8 times 7 which is 56 and yor ratio would be 56:7

6 0

2 years ago

What are the approximate values of the non-integral roots of the polynomial equation?

irga5000 [103]

Answer:

-4, -2, -3-2i, -3+2i

Step-by-step explanation:

The of the polynomial equation are those values of x, for which f(x)=0.

Consider equation

$f(x)=0\\ \\(x^2+6x+8)(x^2+6x+13)=0$

By zero product property,

$x^2+6x+8=0\ \text{or}\ x^2+6x+13=0$

Solve each equation:

1. $x^2+6x+8=0$

$D=6^2-4\cdot 8=36-32=4\\ \\x_{1,2}=\dfrac{-6\pm \sqrt{4}}{2}=\dfrac{-6\pm 2}{2}=-4,\ -2$

2. $x^2+6x+13=0$

$D=6^2-4\cdot 13=36-52=-16=16i^2\\ \\x_{1,2}=\dfrac{-6\pm \sqrt{16i^2}}{2}=\dfrac{-6\pm 4i}{2}=-3-2i,\ -3+2i$

5 0

2 years ago

Read 2 more answers

Y=-2x+4

goldenfox [79]

I think it is the first one

5 0

2 years ago