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Firlakuza [10]
3 years ago
15

Emily wants to find out if the carpool line around her school causes too much traffic on neighborhood roads. which is a valid sa

mple for her survey? 25 teachers at the school 25 families living near the school 25 students waiting for carpool rides 25 parents of students who ride the bus to and from school
Mathematics
2 answers:
ivanzaharov [21]3 years ago
4 0
25 families living near her school
Arada [10]3 years ago
3 0

Answer:

Emily wants to find out if the carpool line around her school causes too much traffic on neighborhood roads.The valid sample of the survey is

As the problem is faced by the one of the member of the school , and most of the members would nod this.

As, teacher being the most respected person in that colony, and if they are honest ,

The survey of 25 teachers at the school , will give the best possible result.

But,the better result is given by, 25 members located around that area, because if there is a problem with carpooling, most of the members around that area will be mostly affected by this.And the best solution is to take their  opinion.

So, Option (B)  25 families living near the school , looks best options among the given option provided.

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B

Step-by-step explanation:

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The Venn diagram shows the results of two events resulting from rolling a number cube.
tankabanditka [31]

Answer:

P(A|B)=\frac{2}{3}

P(A)*P(B)=\frac{1}{3}

P(A) =\frac{2}{3}

P(B) =\frac{1}{2}.

Step-by-step explanation:

We use the Venn diagram to calculate the desired probabilities.

Note that there are 6 possible results in the sample space

S = {1, 2, 3, 4, 5, 6}

Then note that in the region representing the intercept of A and B there are two possible values.

So

P (A\ and\ B) = \frac{2}{6} = \frac{1}{3}

In the region that represents event A there are 4 possible outcomes {4, 5, 1, 2}

So

P(A) = \frac{4}{6} = \frac{2}{3}

In the region that represents event B there are 3 possible outcomes {1, 2, 6}

So

P(B) = \frac{3}{6} = \frac{1}{2}.

Now

P(A | B)=\frac{P(A \ and\ B)}{P(B)}\\\\P(A | B)=\frac{\frac{1}{3}}{\frac{1}{2}}\\\\P(A|B)=\frac{2}{3}

P(A)*P(B)=\frac{2}{3}*\frac{1}{2}=\frac{1}{3}

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