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3 years ago

6

if 15 is added to twice a number the result will be equal to that number increased by 23 find the answer what is the equation an

d solve the problem

1 answer:

maw [93]3 years ago

5 0

Hello,

Let's assume x the number

15+2x=x+23
==>2x-x=23-15
==>x=8

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The total number of fungal spores can be found using an infinite geometric series where a1 = 8 and the common ratio is 4. Find t

GalinKa [24]

Answer:

$S_{n} = \frac{2(4^{n}-1) }3} if r>1$

Step-by-step explanation:

Explanation:-

<u>Geometric sequence</u>:-

The geometric sequence is of the form

$a,ar,ar^{2},ar^{3}$ ……… be an infinite sequence

here first term is 'a' and ratio is 'r '

In this geometric sequence 'n' t h term is $t_{n} = a r^{n-1}$ ....(1)

Given data a1 term is '8 ' and ratio is '4'

substitute n=1 in equation(1)

$t_{1} = a r^{1-1}$ = 8

$ar=8$ ...........(2)

substitute r= 4 in equation(2)

now we get a(4)=8

dividing "4" on both sides , we get a = 2

<u>Geometric series</u>:-

$a+ar+ar^{2}+ar^{3}+$ .....is an infinite geometric series.

sum of this infinite series will be the upper limit of the fungal spores

that is we have to find sum of infinite series

$S_{n} = \frac{a(r^{n}-1) }{r-1} if r>1$

$S_{n} = \frac{2(4^{n}-1) }{4-1} if r>1$

$S_{n} = \frac{2(4^{n}-1) }3} if r>1$

<u>Final answer:</u>-

sum of this infinite series will be the upper limit of the fungal spores

$S_{n} = \frac{2(4^{n}-1) }3} if r>1$

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