The intersecting secant-tangent theorem says that
where T is the point at which line segment PO touches the circle. Similarly,
so we have
OP is of course as long as itself, and AO and BO are radii of the same circle so they have the same lengths.
This means triangles APO and BPO are congruent, which means angles APO and BPO are congruent, so angle APB is bisected by PO.
Answer:
SAS
Step-by-step explanation:
JK is congruent to LM (given)
L is midpoint of JN (given)
JL is congruent to LN (definition of midpoint)
JK is parallel to LM (given)
Angle LJK is congruent to Angle NLM (corresponding angles)
Answer:
the answer in false
Step-by-step explanation:
Answer:
0.7999989281
Step-by-step explanation:
x1 = cos^-1 (3/5)
x1= 53.13°
sin(53.13) = 0.7999989281