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suter [353]
4 years ago
15

Which of the following points lies on the graph of this equation?

Mathematics
2 answers:
balu736 [363]4 years ago
8 0

Answer:

C(3,3)

Step-by-step explanation:

iren [92.7K]4 years ago
6 0
C) (3,3) if not then its A) (-3,2)
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1+39(12-44)=x find x
Eduardwww [97]

Answer:

The answer is x=−1247

Step-by-step explanation:

Let's solve your equation step-by-step.

1+39(12−44)=x

Step 1: Simplify both sides of the equation.

1+39(12−44)=x

1+−1248=x

(1+−1248)=x(Combine Like Terms)

−1247=x

−1247=x

Step 2: Flip the equation.

Answer: x=−1247

6 0
3 years ago
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Write the equation of the line in slope-intercept form passing through the points (-4,2) and (1,12)
alexira [117]

Answer:

y = 2x + 10

Step-by-step explanation:

Find the slope:

12 - 2 / 1 - (-4)

10 / 5 = 2

Write in point-slope form:

y - 12 = 2(x - 1)

rearrange:

y - 12 = 2x - 2

y = 2x + 10

6 0
3 years ago
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Anettt [7]
The answer is D! if you sub them in :)
6 0
4 years ago
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My neighbors daughter was playing with a book and tore out the pages7,8,100,101,222 and 223. How many sheets did she tear out?
monitta

Answer:

6

Step-by-step explanation:

3 0
4 years ago
What are the coordinates of the vertex of the function below write your answer in the form y-9= -6(x-1)^2
Oliga [24]

Answer:

The co-ordinates of the vertex of the function y-9= -6(x-1)^2 is (1, 9)

<u>Solution:</u>

Given, equation is y-9=-6(x-1)^{2}

We have to find the vertex of the given equation.

When we observe the equation, it is a parabolic equation,

We know that, general form of a parabolic equation is  y-9=-6(x-1)^{2}

Where, h and k are x, y co ordinates of the vertex of the parabola.

\text { Now, parabola equation is } y-9=-6(x-1)^{2} \rightarrow y=-6(x-1)^{2}+9

By comparing the above equation with general form of the parabola, we can conclude that,

a = -6, h = 1 and k = 9

Hence, the vertex of the parabola is (1, 9).

7 0
3 years ago
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