All categories

3 years ago

How do you prove that ABE is congruent to DBC?

Mathematics

1 answer:

Alla [95]3 years ago

3 0

Prove that abc congreunt to dbc

BE=BC (given)
BAE=CDB ( GIVEN
ABE = CBD (VERTICALLY OPPOSITE ANGLES)
THEREFORE ABE TRAINGLE CONGREUNT TO DBC TRAINGLE.

You might be interested in

Monica and Michael both want to buy a scooter. Monica has already saved $25 and plans to save $5 per week. Michael has $16 and p

Anna71 [15]

3 weeks

Step-by-step explanation:

To find the number of weeks, we have to equate the amount already saved and planned to save by both each week.

So we can write the expression as,

Let w be the number of weeks.

25 + 5w =16 + 8w

Grouping the terms as,

25 - 16 = 8w - 5w

9 = 3w

Dividing both sides by 3, we will get,

3w/3 = 9/3

w = 3

So number of weeks = 3

5 0

2 years ago

An 8.0 kg block is moving at 3.2 m/s. A net force of 10 N is constantly applied on the block in the direction of its movement, u

Softa [21]

Answer:

5.02 m/s

Step-by-step explanation:

We are given that

Mass of block,m=8 kg

Initial velocity,u=3.2 m/s

Net force ,F=10 N

Distance,s=6 m

We have to find the approximate final velocity of the block.

We know that $a=\frac{F}{m}$

Using the formula

$a=\frac{10}{8}=\frac{5}{4} m/s^2$

We know that

$v=\sqrt{u^2+2as}$

Using the formula

$v=\sqrt{(3.2)^2+2\times \frac{5}{4}\times 6}$

$v=5.02 m/s$

8 0

2 years ago

3 turtles walking.

Serggg [28]

Answer:

Divide 250 by 9.4 to get 26.6

Step-by-step explanation:

To calculate her unit rate, 1 minute, we must divide the distance travelled over 9.4 minutes by 9.4 to see how far she travelled in 1 minute.

8 0

2 years ago

Help me please! I need help!

RSB [31]

Answer:

52 and 65 those are the ages of principles between 50%

7 0

2 years ago

You stand a known distance from the base of the tree, measure the angle of elevation the top of the tree to be 15â—¦ , and then

gogolik [260]

Answer:

The maximum possible error of in measurement of the angle is $d\theta_1 =(14.36p)^o$

Step-by-step explanation:

From the question we are told that

The angle of elevation is $\theta_1 = 15 ^o = \frac{\pi}{12}$

The height of the tree is h

The distance from the base is D

h is mathematically represented as

$h = D tan \theta$ Note : this evaluated using SOHCAHTOA i,e

$tan\theta = \frac{h}{D}$

Generally for small angles the series approximation of $tan \theta \ is$

$tan \theta = \theta + \frac{\theta ^3 }{3}$

So given that $\theta = 15 \ which \ is \ small$

$h = D (\theta + \frac{\theta^3}{3} )$

$dh = D (1 + \theta^2) d\theta$

=> $\frac{dh}{h} = \frac{1 + \theta ^2}{\theta + \frac{\theta^3}{3} } d \theta$

Now from the question the relative error of height should be at most

$\pm p$ %

=> $\frac{dh}{h} = \pm p$

=> $\frac{1 + \theta ^2}{\theta + \frac{\theta^3}{3} } d \theta = \pm p$

=> $d\theta = \pm \frac{\theta + \frac{\theta^3}{3} }{1+ \theta ^2} * \ p$

So for $\theta_1$

$d\theta_1 = \pm \frac{\theta_1 + \frac{\theta^3_1 }{3} }{1+ \theta_1 ^2} * \ p$

substituting values

$d [\frac{\pi}{12} ] = \pm \frac{[\frac{\pi}{12} ] + \frac{[\frac{\pi}{12} ]^3 }{3} }{1+ [\frac{\pi}{12} ] ^2} * \ p$

=> $d\theta_1 = 0.25 p$

Converting to degree

$d\theta_1 = (0.25* 57.29) p$

$d\theta_1 =(14.36p)^o$

4 0

2 years ago