Mg(OH)2 + 2 HCl → MgCl2 + 2 H2O
(0.0500 L) x (0.500 mol/L HCl) x (1 mol Mg(OH)2 / 2 mol HCl) x (58.3197 g Mg(OH)2/mol) = 0.729 g = 729 mg Mg(OH)2
<span>(729 mg Mg(OH)2) x (5.00 mL / 400 mg) = 9.11 mL milk of magnesia</span>
Answer:
i. The height of its jump is approximately 0.115 m
ii. The time of flight of its jump is approximately 0.306 seconds
iii. The range of its jump is approximately 0.795 m
Explanation:
The angle at which the grasshopper jumps, θ = 30°
The speed with which the grasshopper takes off, u = 3 m/s
i. The height of its jump 'h', is given by the following relation;
Where;
g = The acceleration due to gravity ≈ 9.81 m/s²
Therefore;
The height of its jump, h ≈ 0.115 m
ii. The time of flight of its jump, 't', is given as follows;
Therefore;
The time of flight of its jump, t ≈ 0.306 seconds
iii. The range of the jump is given by the following projectile motion equation for the range as follows;
Therefore;
The range of the jump, R ≈ 0.795 m.
Answer:
Biphenyl
Explanation:
The reaction of bromo benzene with magnesium-ether solution yields a Grignard reagent.
The byproduct of this reaction is biphenyl. It is formed when two unreacted bromobenzene molecules are coupled together.
Hence, It is advised that the bromobenzene solution be added slowly to the magnesium-ether solution so that it isn't present in a high concentration, thus reducing the amount of biphenyl by-product formed.