Check the picture below.
make sure your calculator is in Degree mode.
Answer:
Area of the shaded portion = (120π + 36√3)sq. m
Step-by-step explanation:
Area of the shaded region = Area of circle - Area of triangle
Given
radius of the circle = 12m
Area of the circle = πr²
Area of the circle = π(12)²
Area of the circle = 144π m²
Area of the sector = theta/360 * πr²
Area of the sector = 60/360 * 12²π
Area of the sector = 60/360 * 144π = 24π
Area of the triangle = 1/2 bh
Area of the triangle = 1/2 (12cos30)(12)
Area of the triangle = 36√3
Area of the shaded portion = (144π - 24π + 36√3)sq. m
Area of the shaded portion = (120π + 36√3)sq. m
<h3>Slopes of perpendicular lines.</h3>
Let k: y = a₁x + b₁ and l: y = a₂x + b₂. Then
<h3>k ║ l ⇔ a₁ = a₂</h3><h3>k ⊥ l ⇔ a₁ · a₂ = -1</h3>
We have the line y = -x + 5 ⇒ a₁ = -1.
Therefore
a₂ · (-1) = -1
-a₂ = -1 I<em>change the signs</em>
<h2>a₂ = 1</h2>
Add them all up then divide then by 4 you will get 19.75cm