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Bumek [7]
3 years ago
15

Solve the inequality. 4(x – 3) – 2x ≥ 5 – (x + 2)

Mathematics
2 answers:
Anni [7]3 years ago
6 0
4(x - 3) - 2x \geq5 - (x + 2)\\
4x-12-2x\geq5-x-2\\
3x\geq15\\
x\geq5

Sidana [21]3 years ago
3 0
4(x-3)-2x\geq5-(x+2)\\\\4x-12-2x\geq5-x-2\\\\2x-12\geq3-x\ \ \ \ /+12\\\\2x\geq15-x\ \ \ \ /+x\\\\3x\geq15\ \ \ \ /:3\\\\x\geq5\\\\x\in\left< 5;\ \infty\right)
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Thank you for posting your question here in brainly. The answer to the above equation is letter C which is <span> x + 9 remainder –9. Please see below solution:

x2 + 17x + 63 / x + 8 = x + 9 r-9
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