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2 years ago

Write the phrase as a variable expression. Use x to represent "a number."

Mathematics

2 answers:

Naddika [18.5K]2 years ago

7 0

Answer:

a/9 - 4

Step-by-step explanation:

navik [9.2K]2 years ago

5 0

Answer:

a/9 - 4

Step-by-step explanation:

You might be interested in

I think u guys know what to do !!!

kotykmax [81]

Answer:

B, C

Step-by-step explanation:

7 - x = 18

7 - 2x = 18 - x

126 - 14x = 324 - 18x

We are nowhere near the solution.

-x = 11

x = -11

This works.

7 = x + 18

-11 = x

This works.

25 - x = 36

-25 + x = -36

This does not help.

7 = x + 18

0 = x + 11

We still do not have a solution.

Answer: B, C

4 0

2 years ago

missy bought 4 bags of chocolates. each bag had 8 pieces of chocolate in it . after her kids ate 6 of the chocolate missy packed

Novay_Z [31]

Answer:

There will be 2 numbers of individual bags of chocolates left with Missy.

Step-by-step explanation:

Missy bought 4 bags of chocolates and there are 8 pieces of chocolates in each bag.

Therefore, there was a total (4× 8) = 32 chocolates.

Now, her kids ate 6 of the chocolates.

So, there remains (32 - 6) = 26 chocolates left.

If Missy packed the remaining chocolates into individual bags with 13 chocolates in each bag, then there will be $\frac{26}{13} =2$ numbers of individual bags of chocolates left with Missy. (Answer)

5 0

3 years ago

Linda, Tony, and deon have a total of $99 in their wallets. Tony's has 4 times what deon has. Linda has $9 more than Deon. How m

Westkost [7]

Answer:its 9 just ook the tsest

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers

Two integers have a sum of -44 and a difference of 22. The greater of the two integers is

Leni [432]

Answer:

-11

Step-by-step explanation:

The generic solution to ...

a + b = sum
a - b = difference

Can be found by adding the two equations:

(a+b) + (a-b) = (sum) + (difference)

2a = (sum + difference)

a = (sum + difference)/2

___

Our particular solution is ...

a = (-44 +22)/2 = -11

The greater of the two numbers is -11.

___

The other number is -33.

5 0

3 years ago

1. an alloy contains zinc and copper in the ratio of 7:9 find weight of copper of it had 31.5 kgs of zinc.

m_a_m_a [10]

Answer:

Step-by-step explanation:

Question (1). An alloy contains zinc and copper in the ratio of 7 : 9.

If the weight of an alloy = x kgs

Then weight of copper = $\frac{9}{7+9}\times (x)$

= $\frac{9}{16}\times (x)$

And the weight of zinc = $\frac{7}{7+9}\times (x)$

= $\frac{7}{16}\times (x)$

If the weight of zinc = 31.5 kg

31.5 = $\frac{7}{16}\times (x)$

x = $\frac{16\times 31.5}{7}$

x = 72 kgs

Therefore, weight of copper = $\frac{9}{16}\times (72)$

= 40.5 kgs

2). i). 2 : 3 = $\frac{2}{3}$

4 : 5 = $\frac{4}{5}$

Now we will equalize the denominators of each fraction to compare the ratios.

$\frac{2}{3}\times \frac{5}{5}$ = $\frac{10}{15}$

$\frac{4}{5}\times \frac{3}{3}=\frac{12}{15}$

Since, $\frac{12}{15}>\frac{10}{15}$

Therefore, 4 : 5 > 2 : 3

ii). 11 : 19 = $\frac{11}{19}$

19 : 21 = $\frac{19}{21}$

By equalizing denominators of the given fractions,

$\frac{11}{19}\times \frac{21}{21}=\frac{231}{399}$

And $\frac{19}{21}\times \frac{19}{19}=\frac{361}{399}$

Since, $\frac{361}{399}>\frac{231}{399}$

Therefore, 19 : 21 > 11 : 19

iii). $\frac{1}{2}:\frac{1}{3}=\frac{1}{2}\times \frac{3}{1}$

$=\frac{3}{2}$

$\frac{1}{3}:\frac{1}{4}=\frac{1}{3}\times \frac{4}{1}$

= $\frac{4}{3}$

Now we equalize the denominators of the fractions,

$\frac{3}{2}\times \frac{3}{3}=\frac{9}{6}$

And $\frac{4}{3}\times \frac{2}{2}=\frac{8}{6}$

Since $\frac{9}{6}>\frac{8}{6}$

Therefore, $\frac{1}{2}:\frac{1}{3}>\frac{1}{3}:\frac{1}{4}$ will be the answer.

IV). $1\frac{1}{5}:1\frac{1}{3}=\frac{6}{5}:\frac{4}{3}$

$=\frac{6}{5}\times \frac{3}{4}$

$=\frac{18}{20}$

$=\frac{9}{10}$

Similarly, $\frac{2}{5}:\frac{3}{2}=\frac{2}{5}\times \frac{2}{3}$

$=\frac{4}{15}$

By equalizing the denominators,

$\frac{9}{10}\times \frac{30}{30}=\frac{270}{300}$

Similarly, $\frac{4}{15}\times \frac{20}{20}=\frac{80}{300}$

Since $\frac{270}{300}>\frac{80}{300}$

Therefore, $1\frac{1}{5}:1\frac{1}{3}>\frac{2}{5}:\frac{3}{2}$

V). If a : b = 6 : 5

$\frac{a}{b}=\frac{6}{5}$

$=\frac{6}{5}\times \frac{2}{2}$

$=\frac{12}{10}$

And b : c = 10 : 9

$\frac{b}{c}=\frac{10}{9}$

Since a : b = 12 : 10

And b : c = 10 : 9

Since b = 10 is common in both the ratios,

Therefore, combined form of the ratios will be,

a : b : c = 12 : 10 : 9

7 0

2 years ago