To subtract? as minus means subract/take away?
Answer:
The correct option is A.
Step-by-step explanation:
Domain:
The expression in the denominator is x^2-2x-3
x² - 2x-3 ≠0
-3 = +1 -4
(x²-2x+1)-4 ≠0
(x²-2x+1)=(x-1)²
(x-1)² - (2)² ≠0
∴a²-b² =(a-b)(a+b)
(x-1-2)(x-1+2) ≠0
(x-3)(x+1) ≠0
x≠3 for all x≠ -1
So there is a hole at x=3 and an asymptote at x= -1, so Option B is wrong
Asymptote:
x-3/x^2-2x-3
We know that denominator is equal to (x-3)(x+1)
x-3/(x-3)(x+1)
x-3 will be cancelled out by x-3
1/x+1
We have asymptote at x=-1 and hole at x=3, therefore the correct option is A....
Answer:
x = 2
Step-by-step explanation:
logx + log(2x - 1) = log 6
Apply log rules,
x(2x - 1) = 6
2x^2 - 1x = 6
x = 2 (true) or x = -3/2 (False)
Answer:
4!
Step-by-step explanation:
The answer is not 8, its 4. Just took the test!
Right next to the zero van I heht brainleist please
