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Mazyrski [523]
3 years ago
12

Which BEST describes a horizontal stretch?

Mathematics
2 answers:
Margaret [11]3 years ago
8 0
In a simple Cartesian plane, there are two axes, y-axis that is drawn vertically and the x-axis that is drawn horizontally. this problem asks for the an example of horizontal stretch. Thus, the example of horizontal stretch is the stretching of the graph away from the x-axis. Thus, the answer is letter C. 
Sonbull [250]3 years ago
7 0

The correct answer is "The graph is stretched away from the y-axis."

You might be interested in
How to write 20/10 as a mixed number
Rasek [7]
You can't the answer is 2 because 20 goes into 10 twice
8 0
3 years ago
Read 2 more answers
Can someone help me ? i have no clue how to figure this out
Ad libitum [116K]

\cos t (\sec t - \cos t) = \sin^2 t

\cos t (\dfrac{1}{\cos t} - \cos t) = \sin^2 t

\dfrac{\cos t}{\cos t} - \cos^2 t = \sin^2 t

1 - \cos^2 t = \sin^2 t

Use the identity: \sin^2 t + \cos^2 t = 1 and solve for \sin^2 t. You get: \sin^2 t = 1 - \cos^2 t

Do the substitution on the left side to get:

\sin^2 t = \sin ^2 t

5 0
3 years ago
Read 2 more answers
Find the sum of the first five terms using the geometric series formula for the sequence 1/2, -1,2,-4…
sammy [17]

The sum of the first five terms is 11/2

<h3>How to determine the sum?</h3>

The series is given as:

1/2, -1,2,-4…

Calculate the common ratio of the series using

r = -4/2

Evaluate

r = -2

The sum is then calculated as:

S_n = a\frac{1 - r^n}{1 - r}

This gives

S_n = \frac{1}{2} * \frac{(1 - (-2)^5}{1 + 2}

Evaluate

S_n = \frac{1}{2} * \frac{33)}{3}

Evaluate

S_n =\frac{11}{2}

Hence, the sum of the first five terms is 11/2

Read more about series at:

brainly.com/question/11346378

#SPJ1

7 0
1 year ago
Plz help!
beks73 [17]

First, you need to find the derivative of this function.  This is done by multiplying the exponent of the variable by the coefficient, and then reducing the exponent by 1.  

f'(x)=3x^2-3

Now, set this function equal to 0 to find x-values of the relative max and min.

0=3x^2-3

0=3(x^2-1)

0=3(x+1)(x-1)

x=-1, 1

To determine which is the max and which is the min, plug in values to f'(x) that are greater than and less than each.  We will use -2, 0, 2.

f'(-2)=3(-2)^2-3=3(4)-3=12-3=9

f'(0)=3(0)^2-3=3(0)-3=0-3=-3

f'(2)=3(2)^2=3(4)-3=12-3=9

We examine the sign changes to determine whether it is a max or a min.  If the sign goes from + to -, then it is a maximum.  If it goes from - to +, it is a minimum.  Therefore, x=-1 is a relative maximum and x=1 is a relative miminum.

To determine the values of the relative max and min, plug in the x-values to f(x).

f(-1)=(-1)^3-3(-1)+1=-1+3+1=3

f(1)=(1)^3-3(1)+1=1-3+1=-1

Hope this helps!!

7 0
3 years ago
Answer all 3 please will mark as brainiest
steposvetlana [31]

Answer:

1a. -4 3/5

1b. -4 3/5

2. 33

Step-by-step explanation:

1a. -4 4/5 + 1/5 = -4 3/5

1b. -4 2/5 + (-1/5) = -4 3/5

2. (-16 -35) + 18 = -33

You would need to draw the number 33 to get a score of 0.

5 0
3 years ago
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