answer:
Contd.
Explanation:
We will use the following well-known
Result : The eqn. of a line l passing through the pt. of
intersection of the lines l1:a1+b1+c1=0andl2:a2x+b2y+c2=0 is of
the form
Result :
For the sequence of events, the probability of being assigned 012 is:
P(012)=(1/4)(1/10)(1/10)
P(012)=1/400 (0.25%)
Answer:
Plane A and QRV intersection line is QR.
Explanation:
The plane QRV contains the rectangle QRVN. This rectangle intersects the plane A in the line QR.
Plane A and QRV intersection line is QR.
If one knows a specific line in one plane (for example, two points in the plane), and this line intersects the other plane, then its point of intersection.
Thus, it is on the line of intersection for the two planes.
I believe the answer to this is:
8:<u>35</u>
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Hope this helps! :D
159
10 squared is 100
Do the 5+3 next to get 8 then square the 8 to get 64
That leaves you with 100+64-5=159
