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polet [3.4K]
3 years ago
15

Math help pls? Picture attached.

Mathematics
1 answer:
stich3 [128]3 years ago
8 0
I think it's A, but I'm not sure
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Consider the function below. f(x) = ln(x4 + 27) (a) Find the interval of increase. (Enter your answer using interval notation.)
andrezito [222]

Answer:

a) The function is constantly increasing and is never decreasing

b) There is no local maximum or local minimum.

Step-by-step explanation:

To find the intervals of increasing and decreasing, we can start by finding the answers to part b, which is to find the local maximums and minimums. We do this by taking the derivatives of the equation.

f(x) = ln(x^4 + 27)

f'(x) = 1/(x^2 + 27)

Now we take the derivative and solve for zero to find the local max and mins.

f'(x) = 1/(x^2 + 27)

0 = 1/(x^2 + 27)

Since this function can never be equal to one, we know that there are no local maximums or minimums. This also lets us know that this function will constantly be increasing.

6 0
3 years ago
(50 points) need help with khan practice geometry
Vedmedyk [2.9K]

The awnser is 60 because

It is a cube so it has the smae amout of sides

8 0
2 years ago
Write the following phrase as a variable expression. Use x to represent​ "a number".
mojhsa [17]
Sum means add, a number means x, and four means, uh, 4...

x+4. is what you're looking for
3 0
3 years ago
What is the integral of -3x^3
Sati [7]
\int -3x^3\, dx=-3\int x^3 \, dx=-3\cdot\dfrac{x^4}{4}+C=\dfrac{3x^4}{4}+C
6 0
3 years ago
Help plzzzzzzzzzzzzzzzzz
Butoxors [25]

Answer:

6 % is the answer

Step-by-step explanation:

6.50 x 6%=0.39

6.50+0.39=6.89

4 0
3 years ago
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