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qwelly [4]
4 years ago
5

Can the equation y=1 be written in the form y=mx+b?

Mathematics
2 answers:
vesna_86 [32]4 years ago
8 0

Since y=1 does not have a slope because no x is found, this would be already written in the slope intercept form as y= 0x + 1

This would look like a horizontal line across the y intercept which in this case it would be 1

Svetach [21]4 years ago
5 0

It is technically in the format, it just doesn't have a slope which is why x isn't involved. Otherwise it would look weird to put y=0x+1 even though it would help to comprehend it.

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Use completing the square to solve this quadratic equation.
borishaifa [10]

Step-by-step explanation:

x² + 6x + 9 = 2

(x + 3)² = 2

x + 3 = ±sqrt(2)

x = -3 ± sqrt(2)

so, B and D are correct.

control :

(-3 + sqrt(2))² + 6(-3 + sqrt(2)) + 9 = 2

9 + 2 - 6sqrt(2) - 18 + 6sqrt(2) + 9 = 2

2 = 2

correct

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correct

(3 + sqrt(2))² + 6(3 + sqrt(2)) + 9 = 2

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wrong.

(3 - sqrt(2))² + 6(3 - sqrt(2)) + 9 = 2

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wrong.

7 0
3 years ago
(60 POINTS) Please explain this in detail
Alik [6]

H=D

O=C

B=M

R=A

M=B

First we will prove that the diagonals are bisectors of each other.

Angle DBA is congruent to angle BDC.

Angle CMD is congruent to angle AMB.

Triangle CMD is congruent to triangle AMB.

Segment AM is congruent to segment MC.

M is the midpoint of segment AC.

Segment BD bisects segment AC.

Segment BM is congruent to segment MD.

M is the midpoint of segment BD.

Segment AC bisects segment BD.

Then we will prove that the diagonals are perpendicular to each other.

10. Segment CD is congruent to segment CB.

11. Segment BM is congruent to segment MB.

12. Segment CM is congruent to segment CM.

13. Triangle CDM is congruent to triangle CBM.

14. Angle CMD is congruent to triangle BMC.

15. Angle CMD + angle BMC = 180

16. Angle CMD = 90 and angle BMC = 90

17. Angle AMB = 90

18. Angle CMD is congruent to angle DMA.

19. Angle DMA = 90

20. Segment AC is perpendicular to segment BD.


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