Question

Find the length of a line segment whose endpoints are (-2,3) and (6,3)

Answer 1

Answer:

8

Step-by-step explanation:

Since we want to find the length of a line segment, we can use the distance formula.

$d=\sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1} )^2 }$

(x₁, y₁) and (x₂, y₂) are the points given.

The points we are given are: (-2,3) and (6,3). Therefore,

$\\x_{1} =-2\\y_{1}=3 \\x_{2} = 6\\y_{2} =3$

Plug each value into the formula.

$d=\sqrt{{(6--2})^2+(3-3 )^2} }$

Evaluate inside of the parentheses first.

$d=\sqrt{(6+2)^2+(0)^2}$

$d= \sqrt{(8)^2+(0)^2 }$

Evaluate the exponents.

8²= 8*8=64

$d=\sqrt{64+(0)^2}$

0²= 0*0= 0

$d=\sqrt{64+0}$

Add 64 and 0.

$d=\sqrt{64}$

Take the square root of 64.

$d= 8$

The length of the line segment is 8

Answer 2

The length would be eight bc -1 -2 0 1 2 3 4 5 6