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Alexandra [31]
3 years ago
10

Find the highest common factor of 120 and 150

Mathematics
2 answers:
Sloan [31]3 years ago
4 0

Answer:

30

Step-by-step explanation:

The factors of 120 are: 1, 2, 3, 4, 5, 6, 8, 10, 12, 15, 20, 24, <u>30</u>, 40, 60, 120

The factors of 150 are: 1, 2, 3, 5, 6, 10, 15, 25, <u>30</u>, 50, 75, 150

Then the greatest common factor is 30.

Thepotemich [5.8K]3 years ago
3 0
The highest common factor is 13
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fenix001 [56]

Answer:

2,4 and 7 do not form a triangle

Step-by-step explanation:

To form a triangle, knowing the 3 sides, then

The sum of any 2 sides must be greater than the third side

Consider 2, 4, 7

2 + 4 = 6 < 7

2 + 7 = 9 > 4

4 + 7 = 11 > 2

Since 2 + 4 < 7

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3 years ago
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(2 + i)(3 - i)(1 + 2i)(1 - i)(3 + i)
anygoal [31]

Answer:

<h2>50+50i</h2>

Step-by-step explanation:

Given the expression (2 + i)(3 - i)(1 + 2i)(1 - i)(3 + i), we are to take the product of all the complex values. We must note that i² = -1.

Rearranging the expression [(3 - i)(3 + i)] [(2 + i)(1 - i)](1 + 2i)

On expansion

(3 - i)(3 + i)

=  9+3i-3i-i²

= 9-(-1)

= 9+1

(3 - i)(3 + i) = 10

For the expression (2 + i)(1 - i), we have;

(2 + i)(1 - i)

= 2-2i+i-i²

= 2-i+1

= 3-i

Multiplying 3-i with the last expression (1 + 2i)

(2 + i)(1 - i)(1 + 2i)

= (3-i)(1+2i)

= 3+6i-i-2i²

= 3+5i-2(-1)

= 3+5i+2

= 5+5i

Finally,  [(3 - i)(3 + i)] [(2 + i)(1 - i)(1 + 2i)]

= 10(5+5i)

= 50+50i

Hence,  (3 - i)(3 + i)(2 + i)(1 - i)(1 + 2i) is equivalent to 50+50i

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Answer: 11 1/7

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