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STALIN [3.7K]
2 years ago
14

Which expressionis equal to (-7x+5.1y)-(-9x+5.3y)

Mathematics
1 answer:
Furkat [3]2 years ago
7 0

Answer:

The simplified expression for the given expression will be:

c. 2x-0.2y

Step-by-step explanation:

Given expression:

(-7x+5.1y)-(-9x+5.3y)

To simplify the expression.

Solution:

In order to simplify the expression, we will first remove the parenthesis by reversing the signs of the terms inside the parenthesis which lies after a negative sign out side the parenthesis.

<em>This is because negative multiplies to a negative to give a positive and negative multiplies to a positive to give a negative.</em>

So, we have:

⇒ -7x+5.1y+9x-5.3y

Combining like terms

⇒ -7x+9x+5.1y-5.3y

<em>The like terms can be evaluated as</em>

-7x+9x=2x

5.1y-5.3y=-0.2y

Thus, the simplified expression will be:

⇒  2x-0.2y

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3 years ago
In a group of 10 ​kittens, 5 are female. Two kittens are chosen at random. ​a) Create a probability model for the number of male
olya-2409 [2.1K]

Answer:

(b) Expected number of male kitten E(x) = 1

(c) Standard deviation is ±\frac{2}{3}.

Step-by-step explanation:

Given that,

Number of kittens in a group are 10. Out of these 5 are female.

To find:- (a) create a probability model of male kitten chosen.

    So,  total number of kitten = 10

           number of female kitten = 5    

then, Number of male kitten = 10-5= 5

Now total number of ways to choosing two kittens from group of 10 = ^{10} C_{2}

                                                                                                                 = \frac{10!}{2!\times8!}

                                                                                                                 = 45

for choosing (i) No male P(x=0) = P(Two female) =  \frac{^{5} C_{2}}{45}

                                                                           = \frac{2}{9}

                     (ii) 1 male P(x=1) = P(1 male and 1 female) = \frac{^{5} C_{1}\times^{5} C_{1}}{45} =  \frac{25}{45} =\frac{5}{9}

                     (iii) 2 male P(x=2)= P(2 male) =\frac{^{5} C_{2}}{45} =  \frac{2}{9}

      x_{i}                             0                     1                      2

P(X=x_{i})                           \frac{2}{9}                      \frac{5}{9}                      \frac{2}{9}

(b) what is expected number of male kittens chosen ?

    Expected number of male kitten E(x) =  o\times \frac{2}{9} + 1\times \frac{5}{9} + 2\times\frac{2}{9}

                                                                  = 1

(c) what is standard deviation ?

                              \sigma(x) = \sqrt{ (E(x^{2} )-(Ex)^{2})

No,                          

                               Ex^{2} =o\times \frac{2}{9} + 1\times \frac{5}{9} + 4\times\frac{2}{9}

                                       = \frac{13}{9}

                               \sigma(x)=\sqrt{\frac{13}{9} - 1 }=\sqrt{\frac{4}{9} }  

                                       = ± \frac{2}{3}

                               

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What is the fractional equivalent of 0.2323? <br><br> 23/99<br><br> 23/999<br><br> 2/9
morpeh [17]
It should be 23/99

23/99= 0.232323...
23/999= 0.023023023....
2/9= 0.222222....

Final answer: 23/99
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3 years ago
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Answer:

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Step-by-step explanation:

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6 0
1 year ago
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Answer: Sams club

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