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3 years ago

7

What is the measure of LD?

1 answer:

jekas [21]3 years ago

6 0

The angle measures A)73° i just did the same thing in class xD

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Fifteen years from now Ravi's age will be four times his present age.What is Ravi's present age ? Frame the equation and solve.

Archy [21]

Answer:

Ravi's age after 15 years = x+15

Ravi's age = 4 times his present age = 4x

According to question -

15 + x = 4x

=> 15 = 4x-x = 3x

=> 15 = 3x

=> x = 15/3

=> x = 5

Thus , Ravi's present age is 5 years.

Step-by-step explanation:

7 0

3 years ago

Chen chooses a prime number he multiple s it by 10 and then rounds it to the nearest hundred his answer is 400 write all the pos

poizon [28]

It would most likely be 41 because when you would round 41 after you would × 41 times 10 equals 410 then you would round it to 400

6 0

3 years ago

Please help is for now

telo118 [61]

Answer:

$2$

Step-by-step explanation:

Given:

$-2(1-4x)=3x+8$

Let's distribute the parenthesis

$-2+8x=3x+8$

Let's subtract $-3x$ from both sides

$-2+5x=8$

Let's add $2$ to both sides

$5x=10$

Now, let's divide both sides by $5$ to get $x$ alone

$x=2$

Hope this is helpful

7 0

2 years ago

Read 2 more answers

Which formula can be used to find the nth term of a geometric sequence where the fifth term is 1/6 and the common ratio is 1/4?

OlgaM077 [116]

Answer:

$a_n = 16(\frac{1}{4})^{n - 1}$

Step-by-step explanation:

Given:

Fifth term of a geometric sequence = $\frac{1}{16}$

Common ratio (r) = ¼

Required:

Formula for the nth term of the geometric sequence

Solution:

Step 1: find the first term of the sequence

Formula for nth term of a geometric sequence = $ar^{n - 1}$ , where:

a = first term

r = common ratio = ¼

Thus, we are given the 5th term to be ¹/16, so n here = 5.

Input all these values into the formula to find a, the first term.

$\frac{1}{16} = a*\frac{1}{4}^{5 - 1}$

$\frac{1}{16} = a*\frac{1}{4}^{4}$

$\frac{1}{16} = a*\frac{1}{256}$

$\frac{1}{16} = \frac{a}{256}$

Cross multiply

$1*256 = a*16$

Divide both sides by 16

$\frac{256}{16} = \frac{16a}{16}$

$16 = a$

$a = 16$

Step 2: input the value of a and r to find the nth term formula of the sequence

nth term = $ar^{n - 1}$

nth term = $16*\frac{1}{4}^{n - 1}$

$a_n = 16(\frac{1}{4})^{n - 1}$

3 0

3 years ago

Cos (90-theta) • cosec90-theta) =tano. How?

denis-greek [22]

Answer:

<u>______________________________________________________</u>

<u>TRIGONOMETRY IDENTITIES TO BE USED IN THE QUESTION :-</u>

For any right angled triangle with one angle α ,

$\cos (90 - \alpha ) = \sin \alpha$ or $\sin(90 - \alpha ) = \cos\alpha$

$cosec \: (90 - \alpha ) = \sec\alpha$ or $\sec(90 - \alpha ) = cosec\:\alpha$

<u>SOME GENERAL TRIGNOMETRIC FORMULAS :-</u>

<u></u> $\sin \alpha = \frac{1}{cosec \: \alpha }$ or $cosec \: \alpha = \frac{1}{\sin \alpha }$

<u></u> $\cos \alpha = \frac{1}{\sec \alpha }$ or $\sec \alpha = \frac{1}{\cos \alpha }$

<u>______________________________________________________</u>

Now , lets come to the question.

In a right angled triangle , let one angle be α (in place of theta) .

So , lets solve L.H.S.

$\cos (90 - \alpha ) \times cosec(90 - \alpha )$

$=> sin\alpha \times \sec\alpha$

$=> \sin\alpha \times \frac{1}{\cos\alpha }$

$=> \frac{\sin\alpha }{\cos\alpha }$

$=> \tan\alpha$ = R.H.S.

∴ L.H.S. = R.H.S. (Proved)

3 0

3 years ago