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3 years ago

Extra points! Write the equation for the vertical line that contains point E(10, –3).

Mathematics

1 answer:

Katarina [22]3 years ago

6 0

Your answer would be B, x = 10. This is because that equation would produce a vertical line (up and down) that crosses every Y value at 10 on the X axis. If you're still confused, this is what the graph would look like.

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Brian invests ?1900 into a savings account. The bank gives 3.5% compound interest for the first 2 years and 4.9% thereafter. How

Scorpion4ik [409]

let's check how much is it after 2 years firstly.

$\bf ~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &1900\\ r=rate\to 3.5\%\to \frac{3.5}{100}\dotfill &0.035\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{yearly, thus once} \end{array}\dotfill &1\\ t=years\dotfill &2 \end{cases} \\\\\\ A=1900\left(1+\frac{0.035}{1}\right)^{1\cdot 2}\implies A=1900(1.035)^2\implies A=2035.3275$

Brian invested the money for 6 years, so now let's check how much is that for the remaining 4 years.

$\bf ~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &2035.3275\\ r=rate\to 4.9\%\to \frac{4.9}{100}\dotfill &0.049\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{yearly, thus once} \end{array}\dotfill &1\\ t=years\dotfill &4 \end{cases}$

$\bf A=2035.3275\left(1+\frac{0.049}{1}\right)^{1\cdot 4}\implies A=2035.3275(1.049)^4 \\\\\\ A\approx 2464.54\implies \boxed{\stackrel{\textit{rounded up }}{A=2465}}$

4 0

3 years ago

30 pts + BRAINLIEST

ivanzaharov [21]

Answer:

Number of permutations = 5040

Step-by-step explanation:

We are given the word 'INNOVATIVE', that has total 10 letters.

Now, we are asked to form words using exactly 4 letters at a time i.e. out of 10 letters we are using 4.

Therefore, the number of permutations that can be formed using 4 letters are = P(10,4)

i.e. $10_{P_{4} }$

= $\frac{10!}{(10-4)!}$

= $\frac{10!}{6!}$

= $\frac{10*9*8*7*6!}{6!}$

= 10*9*8*7

= 5040

8 0

3 years ago

Read 2 more answers

It costs $2.75 to enter an arcade. Each game costs $1.25. You have $14. How many games can you play?

Greeley [361]

Answer:

9 times

Step-by-step explanation:

first you do 14 - 2.75 which equals 11.25. you divide that number by 1.25 which equals 9 in total, getting you your answer

7 0

3 years ago

Read 2 more answers

find four solutions for the following linear equations your answer must include at least two positive numbers for X and at least

sattari [20]

9514 1404 393

Answer:

(-18, 14), (-9, 9), (9, -1), (18, -6)

Step-by-step explanation:

Since there is a 9 in the denominator of the coefficient of x, we will get integer solutions only if x is a multiple of 9. Suitable values meeting the problem requirements are x ∈ {-18, -9, 9, 18}. Then the corresponding values of y are ...

y = -5/9(-18) +4 = 10 +4 = 14

y = -5/9(-9) +4 = 5 +4 = 9

y = -5/9(9) +4 = -5 +4 = -1

y = -5/9(18) +4 = -10 +4 = -6

The four solutions we have found are ...

(-18, 14), (-9, 9), (9, -1), (18, -6)