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jolli1 [7]
2 years ago
15

Situation:

Mathematics
1 answer:
omeli [17]2 years ago
4 0

The half life of the substance is 6.92 days.

<h3>What is the Half life  ?</h3>

Half life can be defined as the time required to reduce the concentration to half of its initial value.

Here the equation given is

\rm N = N_o e^{-kt}

The concentration will reduce to half therefore

\rm   N= \dfrac{N_o}{2}

so,

\rm 39/2 = 39  e^{- 0.1001 * t_{1/2}}

ln 0.5 = - 0.1001 * t(1/2)

-0.693 = -.1001 * t(1/2)

t(1/2) = 6.92 days.

Therefore the half life of the substance is 6.92 days.

To know more about Half Life

brainly.com/question/24710827

#SPJ1

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Answer:

\angle B=\cos^{-1}\left(\dfrac{6.3}{9.8}\right)\\ \\\angle B=\sin^{-1}\left(\dfrac{7.5}{9.8}\right)

Step-by-step explanation:

Consider right triangle ABC with right angle C.

In this triangle,

  • BA = 9.8 in
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Write trigonometric functions:

\cos \angle B=\dfrac{BC}{AB}=\dfrac{6.3}{9.8}\\ \\\sin \angle B=\dfrac{AC}{AB}=\dfrac{7.5}{9.8}

Hence,

\angle B=\cos^{-1}\left(\dfrac{6.3}{9.8}\right)\\ \\\angle B=\sin^{-1}\left(\dfrac{7.5}{9.8}\right)

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Pavlova-9 [17]

Answer:

Multiply the top equation by -3 and the bottom equation by 2

Step-by-step explanation:

Given <u>system of equations</u>:

\begin{cases}4x-2y=7\\3x-3y=15 \end{cases}

To solve the given system of equations by addition, make one of the variables in both equations <u>sum to zero</u>.  To do this, the chosen variable must have the <u>same coefficient</u>, but it should be <u>negative</u> in one equation and <u>positive</u> in the other, so that when the two equations are added together, the variable is <u>eliminated</u>.

<u>To eliminate the </u><u>variable y</u>:

Multiply the top equation by -3 to make the coefficient of the y variable 6:

\implies -3(4x-2y=7) \implies -12x+6y=-21

Multiply the bottom equation by 2 to make the coefficient of the y variable -6:

\implies 2(3x-3y=15) \implies 6x-6y=30

Add the two equations together to <u>eliminate y</u>:

\begin{array}{l r r}& -12x+6y= &-21\\+ & 6x-6y= & 30\\\cline{1-3}& -6x\phantom{))))))} = & 9\end{array}

<u>Solve</u> for x:

\implies -6x=9

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<u>Substitute</u> the found value of x into one of the equations and <u>solve for y</u>:

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To factorize ,

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0.25t = 6 ( divide both sides by 0.25 )

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