Answer:
Yes, It is an binomial experiment.
Step-by-step explanation:
Consider the provided information.
There are 4 conditions to identify that a distribution is binomial or not.
- Binary: That means only two possibility success or failure.
- Fixed number of trials.
- Independent trials.
- The probability of success is constant from trial to trial.
Now consider the provide procedure:
Binary condition is satisfied because baby can be male or not.
Trials are independent because couples were selected randomly. It satisfy the 2nd condition.
There are 70 couples it satisfy the 3rd condition.
Probability of success will be constant as couples selected randomly. It satisfy the 4th condition.
Yes, It is an binomial experiment because procedure satisfies all the criteria for a binomial distribution.
Hence, It is an binomial experiment.
Answer:
(0.5, 1.3)(0.5, 1.3)
Step-by-step explanation:
Given equations are:
As we can see that the given equations are linear equations which are graphed as straight lines on graph. The solution of two equations is the point of their intersection on the graph.
We can plot the graph of both equations using any online or desktop graphing tool.
We have used "Desmos" online graphing calculator to plot the graph of two lines (Picture Attached)
We can see from the graph that the lines intersect at: (0.517, 1.267)
Rounding off both coordinates of point of intersection to nearest tenth we get
(0.5, 1.3)
Hence,
(0.5, 1.3) is the correct answer
Keywords: Linear equations, variables
Answer:
a) Mean 0.11 and standard deviation 0.0044.
b) Mean 0.11 and standard deviation 0.0099.
c) Mean 0.11 and standard deviation 0.0198
Step-by-step explanation:
Central Limit Theorem:
For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean and standard deviation
In this question:
a. For a random sample of size n equals 5000.
Mean:
Standard deviation:
Mean 0.11 and standard deviation 0.0044.
b. For a random sample of size n equals 1000.
Mean:
Standard deviation:
Mean 0.11 and standard deviation 0.0099.
c. For a random sample of size n equals 250.
Mean:
Standard deviation:
Mean 0.11 and standard deviation 0.0198