Answer:
1. = 3xy + x - 2y - 4
2. = d^2(2c^3-8c^2d+3d^2)
Step-by-step explanation:
= 9x^2y^2 + 3x^2y - 6xy^2 - 12xy/3xy
First factor the top equation ….
= 3xy(3xy + x - 2y - 4)/3xy
If the top and the bottom both carry 3xy, you can cancel out both of them leaving you with ….
= 3xy + x - 2y - 4
= -16c^6d^6 + 64c^5d^7 - 24c^3d^8/-8c^3d^4
First factor the top equation ....
= -8c^3d^6(2c^3-8c^2d+3d^2)/-8c^3d^4
If the top and the bottom both carry -8c^3 you can cancel out both of them leaving you with ….
= <u>d^6</u>(2c^3-8c^2d+3d^2)/d^4
Apply the exponent rule with d^6 ....
= <u>d^4</u><u>d^2</u>(2c^3-8c^2d+3d^2)/d^4
cancel out d^4 ....
= d^2(2c^3-8c^2d+3d^2)
Answer:
that is literally so easy just add some type of fraction
Step-by-step explanation:
-.27 1/10
-.27 2/10
-.27 3/10
etc.
To represent this statement I put it in an expression thingy -3 ⩽ p <1
A "regular quadrilateral" is a square, so the length and width are both 4 cm. The surface area of a rectangular prism is given by
S = 2(LW +H(L +W))
S = 2((4 cm)*(4 cm) +(6 cm)*(4 cm +4 cm))
S = 2(16 cm² +48 cm²)
S = 2*64 cm² = 128 cm²
The surface area of the prism is 128 cm².
2 and 5...................... hope I helped
