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Andrews [41]
2 years ago
14

Part A: Solve –vp + 40 < 95 for v. Show your work. (4 points) Part B: Solve 8w – 3r = 45 for r. Show your work. (6 points)

Mathematics
2 answers:
sergiy2304 [10]2 years ago
5 0

(<span>−v</span>)<span>(p)</span>+40<95

−<span>pv</span>+40+<span>−40</span><<span>95+<span>−40</span></span>

−<span>pv</span><<span>55</span>

<span>-pv/-p < 55/-p</span>

<span>v > -55/p</span>

<span> your final answer is -55/p</span>

Naily [24]2 years ago
3 0

Answer:

A)v>-\frac{55}{p}

B)r=\frac{8}{3}w-15

Step-by-step explanation:

A)

The inequality is

–vp + 40 < 95

Subtract 40 to both sides

–vp  < 95 - 40

-vp< 55

Now, divide both sides by -p. Whenever, we divide by a negative number inequality sign changes

v>\frac{55}{-p}\\\\B)The given equation is[tex]8w-3r=45

Subtract 8w to both sides

-3r=45-8w

Divide both sides by -3

r=-15+\frac{8w}{3}\\\\r=\frac{8}{3}w-15

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Hey! Can someone check my answers?
Andrew [12]
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Q1. The answer is <span>A. 5y^6
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20 y^{9} +5 y^{6}= 4*5 y^{9}+5 y^{6}
Since x^{a}* x^{b}  =x^{a+b}, then x^{9}= x^{3}* x^{6}

Back to our expression:
4*5 y^{9}+5 y^{6}=4*5 y^{3}*y^{6}+5 y^{6}=4 y^{3}*5y ^{6}+  5y ^{6}*1=5 y^{6} (4y ^{3} +1)
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We will use the rule  x^{a}* x^{b} =x^{a+b} to factorise the exponents:
12x y^{5}+5*12 x^{4} y^{2} -2*12 x^{3} y^{3}= \\ =12x*y^{2}*y^{3}+5*12*x* x^{3} *y^{2}-2*12x* x^{2} *y*y^{2}= \\ =12xy^{2}*y^{3}+12xy^{2}*5 x^{3} -12xy^{2}*2 x^{2} y= \\ =12xy^{2}(y^{3}+5 x^{3}-2 x^{2} y)
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3 years ago
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Anna35 [415]
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Hope I am right.
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