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3 years ago

What’s the slope-intercept form of y + 3 = 4(x - 5),

Mathematics

2 answers:

Cloud [144]3 years ago

5 0

Slope-intercept form is: y = mx + b

m = slope

b = y-intercept

y + 3 = 4(x - 5)

Distribute the 4

y + 3 = 4x - 20

Subtract 3 from both sides.

y = 4x - 23

kompoz [17]3 years ago

3 0

Answer:

Step-by-step explanation:

Slope intercept form...

y=mx+c

where, m=slope

c=intercept

y + 3 = 4(x - 5)

Open the Brackets.

y + 3 = 4x - 20

SUBTRACT 3 FROM BOTH SIDES.

y + 3 (-3)= 4x - 20 (-3)

Take note of the signs and solve.

y = 4x - 23

4 is the slope.

-23 is the intercept.

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3 years ago

What is the area of a section of pavement that is 10 ft wide and 70 yd long? Give your answer in square feet. I think I have th

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Step-by-step explanation:

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3 years ago

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Answer:

Step-by-step explanation:

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3 years ago

How many terms are there in the sequence 1, 8, 28, 56, ..., 1 ?

BabaBlast [244]

Answer:

9 terms

Step-by-step explanation:

Given:

1, 8, 28, 56, ..., 1

Required

Determine the number of sequence

To determine the number of sequence, we need to understand how the sequence are generated

The sequence are generated using

$\left[\begin{array}{c}n&&r\end{array}\right] = \frac{n!}{(n-r)!r!}$

Where n = 8 and r = 0,1....8

When r = 0

$\left[\begin{array}{c}8&&0\end{array}\right] = \frac{8!}{(8-0)!0!} = \frac{8!}{8!0!} = 1$

When r = 1

$\left[\begin{array}{c}8&&1\end{array}\right] = \frac{8!}{(8-1)!1!} = \frac{8!}{7!1!} = \frac{8 * 7!}{7! * 1} = \frac{8}{1} = 8$

When r = 2

$\left[\begin{array}{c}8&&2\end{array}\right] = \frac{8!}{(8-2)!2!} = \frac{8!}{6!2!} = \frac{8 * 7 * 6!}{6! * 2 *1} = \frac{8 * 7}{2 *1} =2 8$

When r = 3

$\left[\begin{array}{c}8&&3\end{array}\right] = \frac{8!}{(8-3)!3!} = \frac{8!}{5!3!} = \frac{8 * 7 * 6 * 5!}{5! *3* 2 *1} = \frac{8 * 7 * 6}{3 *2 *1} = 56$

When r = 4

$\left[\begin{array}{c}8&&4\end{array}\right] = \frac{8!}{(8-4)!4!} = \frac{8!}{4!3!} = \frac{8 * 7 * 6 * 5 * 4!}{4! *4*3* 2 *1} = \frac{8 * 7 * 6*5}{4*3 *2 *1} = 70$

When r = 5

$\left[\begin{array}{c}8&&5\end{array}\right] = \frac{8!}{(8-5)!5!} = \frac{8!}{5!3!} = \frac{8 * 7 * 6 * 5!}{5! *3* 2 *1} = \frac{8 * 7 * 6}{3 *2 *1} = 56$

When r = 6

$\left[\begin{array}{c}8&&6\end{array}\right] = \frac{8!}{(8-6)!6!} = \frac{8!}{6!2!} = \frac{8 * 7 * 6!}{6! * 2 *1} = \frac{8 * 7}{2 *1} = 28$

When r = 7

$\left[\begin{array}{c}8&&7\end{array}\right] = \frac{8!}{(8-7)!7!} = \frac{8!}{7!1!} = \frac{8 * 7!}{7! * 1} = \frac{8}{1} = 8$

When r = 8

$\left[\begin{array}{c}8&&8\end{array}\right] = \frac{8!}{(8-8)!8!} = \frac{8!}{8!0!} = 1$

The full sequence is: 1,8,28,56,70,56,28,8,1

And the number of terms is 9

3 0

3 years ago

<img src="https://tex.z-dn.net/?f=y%20%3D%20%20%5Cfrac%7B12%7D%7Bx%7D%20%20%5C%5C%20y%20%3D%20%20%5Cfrac%7B6%7D%7B%20%7Bx%7D%5E%

soldi70 [24.7K]

Answer:

x = 1/2

y = 24

Step-by-step explanation:

y = 12 / x

y = 6 / x²

12 / x = 6 / x²

x² / x = 6 / 12

x = 1 / 2

y = 12 / x

y = 12 / (1/2)

y = 24

4 0

3 years ago