Answer:
y = 1/6 x^2 + 8/3 x + 49/6
Step-by-step explanation:
This is a parabola which opens upwards.
The distance of a point (x, y) from the focus is
√[(x - -8)^2 + (y - -1)^2] and
the distance of the point from the line y = -4
= y - -4
These distances are equal for a parabola so:
√[(x - -8)^2 + (y - -1)^2] = y + 4
Squaring both sides:
(x + 8)^2 + (y + 1)^2 = (y + 4)^2
x^2 + 16x + 64 + y^2 + 2y + 1 = y^2 + 8y + 16
x^2 + 16x + 64 + 1 - 16 = 8y - 2y
6y = x^2 + 16x + 49
y = 1/6 x^2 + 8/3 x + 49/6 is the equation of the parabola.
They forget to say "not to scale". I'm guessing this is trig because I don't see another way to do it.
Let's consider x=chord PQ first. By the Law of Cosines
We have an isosceles triangle formed by two radii of 9 cm and x=PQ. By the Law of Cosines again,
The area of the circle is the fraction given by the angle,
Answer: 24.7 sq cm
26.25ft. Have a wonderful day
Answer:
C would be the answer to the first part because the two subtractions is a double negative making it a positve so if you replace that with a addition symbol it will read the absolute value of 125+70 which is 195
Part two the distance is 195 which is found in the first part. Absolute value is the distance from 0.
Part 1. C
Part 2. D
Hope this helps
