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Luda [366]
3 years ago
10

QUICK! The commands available from a menu change depending upon what you are doing. True False

Computers and Technology
2 answers:
Arisa [49]3 years ago
7 0

Answer:

true because it changes depending upon what you were doing so true

g100num [7]3 years ago
5 0

Answer:

true

Explanation:

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3 years ago
The scheme function (mult2-diff Ist) should take one argument, a list of numbers, and results in multiplying each number in the
JulijaS [17]

Answer:

The solution code is written in Python.

  1. def mult2_diff(lst):
  2.    num_list = []
  3.    for x in lst:
  4.        num_list.append(x * 2)
  5.    diff = num_list[0]
  6.    for i in range(1, len(num_list)):
  7.        diff = diff - num_list[i]
  8.    
  9.    print(diff)

Explanation:

Firstly, based on the requirement stated in the question, define a function <em>mult2_diff() </em>that takes one argument, <em>lst</em>, which is a list of numbers (Line 1).

This function is expected to multiply each number in the list by two and then followed with computing the difference. To do so, let's try to attempt the first function task, multiplying numbers.  Create a new list, num_list, to hold the multiplied numbers (Line 2). Use a for loop to traverse through each number in the input list, <em>lst</em>, and multiply each of them by two and add it to the <em>num_list </em>(Line 4-5).

To attempt the second function task, create another variable, <em>diff</em>, to hold the value of calculated difference between the numbers in the <em>num_list</em>. Initialize <em>diff </em>with the first number in the <em>num_list</em>. Use a another for-loop to traverse through each number in the num_list starting with second index, <em>1</em>, and calculate the difference between the <em>diff </em>and the current number extracted from the <em>num_list </em>through indexing.

At last print the output of <em>diff</em> (Line 11).

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3 years ago
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Mademuasel [1]
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5 0
3 years ago
What is the output?
olga55 [171]

Answer:

The output is 28

Explanation:

Required

Determine the output of the code segment

The first line initializes "answer" to 0

The next two lines iterate through lists [2,4] and [3,5

Each of these lists have two elements; So, the number of iterations is 2 * 2 i.e. 4.

In the first iteration

numA = 2, numB = 3, answer = 0

So:

answer = answer + numA + numB= 0 + 2 + 3 = 5

In the second iteration

numA = 2, numB = 5, answer = 5

So:

answer = answer + numA + numB= 5 + 2 + 5 = 12

In the third iteration

numA = 4, numB = 3, answer = 12

So:

answer = answer + numA + numB= 12 + 4 + 3 = 19

In the fourth iteration

numA = 4, numB = 5, answer = 19

So:

answer = answer + numA + numB= 19 + 4 + 5 = 28

Lastly, the value of "answer" is printed

<em>Hence, the output is 28</em>

7 0
3 years ago
Write a function called printRange() that accepts two integers as arguments and prints the sequence of numbers between the two a
a_sh-v [17]

Answer:

def printRange(start, stop, steps = 1):

   list1 = []

   if steps > start or stop:

       print("Steps is larger than start and stop value")

       return None

   if int(start) < int(stop):

       while start < stop:

           start = start + int(steps)

           list1.append(start)

       print(list1)

   elif start > stop:

       while start > stop:

           stop = stop + int(steps)

           list1.append(stop)

       print(list1)

   elif start == stop:

       print(start)

   else:

       print("Values are not integers.")

for easier viewing:

https://www.codepile.net/pile/e95verLk

If you need help understanding comment below.

5 0
2 years ago
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