Divide 60 by however much people was there to get your answer
Hope it works
To solve this you would divide until you can’t. I recommend staying in whole numbers:) I always divide by twos because I think it’s more efficient! 4 divided by 2 is 2 and 30 divided by 2 is 15 sooo (2 hours to 15) hope this helped!
Answer:
a) 0.06 = 6% probability that a person has both type O blood and the Rh- factor.
b) 0.94 = 94% probability that a person does NOT have both type O blood and the Rh- factor.
Step-by-step explanation:
I am going to solve this question treating these events as Venn probabilities.
I am going to say that:
Event A: Person has type A blood.
Event B: Person has Rh- factor.
43% of people have type O blood
This means that 
15% of people have Rh- factor
This means that 
52% of people have type O or Rh- factor.
This means that 
a. Find the probability that a person has both type O blood and the Rh- factor.
This is

With what we have

0.06 = 6% probability that a person has both type O blood and the Rh- factor.
b. Find the probability that a person does NOT have both type O blood and the Rh- factor.
1 - 0.06 = 0.94
0.94 = 94% probability that a person does NOT have both type O blood and the Rh- factor.
F(n-1) = f(n) - 5, based off of the first one
Answer:
Yes they are
Step-by-step explanation:
11(p+q) = 11p + 11q
---------------------------
11p + (7q+ 4q)
= 11p + ( q * (7+4))
= 11p + (q * 11)
= 11p+ 11q
See they are the same