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daser333 [38]
3 years ago
9

Please help me. I don't get this

Mathematics
1 answer:
nlexa [21]3 years ago
3 0
Abtuse! X equals 6! ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ
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Explain how your model for 3/5-1/2 is different from your model for 3/5-3/10
Neko [114]

Answer:

3/5 - 1/2 is 1/10 while 3/5 -3/10 is 3/10

Step-by-step explanation:


5 0
3 years ago
Please help me with math I need help and its suppose to be handed in today
Yakvenalex [24]

Answer:

A=B perioddddd

Step-by-step explanation:

7 0
4 years ago
Nuclear Power Plant Some nuclear power plants utilize "natural draft" cooling towers in the shape of a hyperboloid, a solid obta
luda_lava [24]

Answer:

  592.4 feet

Step-by-step explanation:

The cross section of the tower can be modeled by a hyperbola with its vertex at (x, y) = (100, 360) and its center at (0, 360). The point (x, y) = (200, 0) helps define the equation of it.

Basic form:

  ((x -h)/a)^2 -((y -k)/b)^2 = 1

Filling in (h, k) = (0, 360) and a=100, we can find b using the given point:

  (200/100)^2 -((0-360)/b)^2 = 1

  (360/b)^2 = 3 . . . . . . . . . . . . . . . rearrange, simplify

  b^ = 360^2/3 = 43200

So, the equation of the hyperbola is ...

  x^2/10000 - (y-360)^2/43200 = 1

__

Then for x = 150 (the distance from center at the top, we can find y to be ...

  (150/100)^2 - (y -360)^2/43200 = 1

  1.25 = (y -360)^2/43200

  y = 360 +√(1.25·43200) ≈ 592.379

The height of the tower is about 592.4 feet.

4 0
4 years ago
Ms. minkins drive 338 miles on 13 gallons of gas. what is the unit rate for the averge milles traveled with 1 gallon of gas
Inessa05 [86]
I gallon is 26 miles
7 0
3 years ago
A lawn mower is pushed a distance of 100 ft. Along a horizontal path by a constant force of 60 lbs. Yhe handle of the lawn mower
olga2289 [7]
For this case we have the following equation:
 w = || F || • || PQ || costheta
 Where,
 || F ||: force vector module
 || PQ ||: distance module
 costheta: cosine of the angle between the force vector and the distance vector.
 Substituting values:
 w = (60) * (100) * (cos (45))
 w = 4242.640687 lb.ft
 Answer:
 
The work done pushing the lawn mower is: 
 w = 4242.640687 lb.ft
6 0
4 years ago
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