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fenix001 [56]
3 years ago
10

Eight friends bought a large order of wings. Each of them ate 9 wings. How many total wings were in the order?

Mathematics
2 answers:
marin [14]3 years ago
6 0

Answer:

72 wings

Step-by-step explanation:

1 \:friend = 9 \:wings\\8 \: friends = x\:wings\\\\

Cross Multiply

x = 9\times 8\\\\x = 72 \:wings

salantis [7]3 years ago
5 0

The order came with 72 wings. 72 divided by 9=8, 8 times 9=72

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5(3q-1)5q+15<br><br><br><br> Who can find the variable for this
Natali [406]

Answer:

<h3>-5(2q - 3)</h3>

Step-by-step explanation:

5(3q - 1)5q + 15 \\ 15q - 5 \times 5q + 15 \\ 15q - 25q + 15 \\  - 10q + 15 \\  - 5(2q - 3) \\

7 0
3 years ago
What is the volume of the cylinder below?
Anestetic [448]

Volume = πr²h


3.14 * (18 : 2)² * 12 =

3.14 * 9² * 12 =

3.14 * 81 * 12 =

254.34 * 12 =


3052,08 mm³



7 0
3 years ago
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Rectangle B is shown below. Nadia drew a scaled version of Rectangle B using a scale factor of = and labeled
Lina20 [59]

Answer:

The area of rectangle C is 2

Step-by-step explanation:

Using a scale factor of \frac{1}{5} yields the side lengths of 1 and 2

(1)(2)=2

4 0
4 years ago
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The ground-state wave function for a particle confined to a one-dimensional box of length L is Ψ=(2/L)^1/2 Sin(πx/L). Suppose th
Hitman42 [59]

Answer:

(a) 4.98x10⁻⁵

(b) 7.89x10⁻⁶

(c) 1.89x10⁻⁴

(d) 0.5

(e) 2.9x10⁻²  

Step-by-step explanation:  

The probability (P) to find the particle is given by:

P=\int_{x_{1}}^{x_{2}}(\Psi\cdot \Psi) dx = \int_{x_{1}}^{x_{2}} ((2/L)^{1/2} Sin(\pi x/L))^{2}dx  

P = \int_{x_{1}}^{x_{2}} (2/L) Sin^{2}(\pi x/L)dx     (1)

The solution of the intregral of equation (1) is:

P=\frac{2}{L} [\frac{X}{2} - \frac{Sin(2\pi x/L)}{4\pi /L}]|_{x_{1}}^{x_{2}}  

(a) The probability to find the particle between x = 4.95 nm and 5.05 nm is:

P=\frac{2}{100} [\frac{X}{2} - \frac{Sin(2\pi x/100)}{4\pi /100}]|_{4.95}^{5.05} = 4.98 \cdot 10^{-5}    

(b) The probability to find the particle between x = 1.95 nm and 2.05 nm is:

P=\frac{2}{100} [\frac{X}{2} - \frac{Sin(2\pi x/100)}{4\pi /100}]|_{1.95}^{2.05} = 7.89 \cdot 10^{-6}  

(c) The probability to find the particle between x = 9.90 nm and 10.00 nm is:

P=\frac{2}{100} [\frac{X}{2} - \frac{Sin(2\pi x/100)}{4\pi /100}]|_{9.90}^{10.00} = 1.89 \cdot 10^{-4}    

(d) The probability to find the particle in the right half of the box, that is to say, between x = 0 nm and 50 nm is:

P=\frac{2}{100} [\frac{X}{2} - \frac{Sin(2\pi x/100)}{4\pi /100}]|_{0}^{50.00} = 0.5

(e) The probability to find the particle in the central third of the box, that is to say, between x = 0 nm and 100/6 nm is:

P=\frac{2}{100} [\frac{X}{2} - \frac{Sin(2\pi x/100)}{4\pi /100}]|_{0}^{16.7} = 2.9 \cdot 10^{-2}

I hope it helps you!

3 0
4 years ago
The length of a rectangle is 10m greater than the width. The area is 24m^2
Ivan

Answer:

length: 12m

width: 2m

Step-by-step explanation:

24 = a*w

a = w+10

then:

24 = (w+10)w

24 = w*w + 10*w

24 = w² + 10w

0 = w² + 10 - 24

w = {-10±√((10²)-(4*1*-24))} / (2*1)

w = {-10±√(100+96)} / 2

w = {-10±√196} / 2

w = {-10±14} / 2

only positive numbers:

w = {-10+14}/2

w = 4/2

w = 2m

a = w+10

a = 2 + 10

a = 12m

Check:

24 = 12*2

5 0
4 years ago
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