Answer:
The maximum height of the ball is 256m
Step-by-step explanation:
Given the equation of a pathway modelled as pathway can be modeled by h = -16t² + 128t
At maximum height, the velocity of the ball is zero.
velocity = dh/dt
velocity = -32t + 128
Since v = 0 at maximum height
0 = -32t+128
32t = 128
t = 128/32
t = 4seconds
The maximum height can be gotten by substituting t = 4 into the modelled equation.
h = -16t² + 128t
h = -16(4)²+128(4)
h = -16(16)+512
h = -256+512
h = 256m
The length would be 18 inches and the width would be 9 inches since the length is twice its width and to find perimeter you do length x 2 and width x 2 and add it together so 18x2 = 36 and 9x2 = 18. 36 + 18 = 54
Answer: I’m not sure if this is it but 16.65 maybe
Step-by-step explanation:
it’s hard to figure out
Answer:
d is equal to or greater than 9
Step-by-step explanation:
Subract thirteen from both sides of the equation.
