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3 years ago

Can someone help me solve for U

Mathematics

1 answer:

ELEN [110]3 years ago

3 0

Answer:

54°

Step-by-step explanation:

We see that 54° and u are corresponding angles of parallel lines. With parallel lines, corresponding angles are congruent, hence, u = 54°.

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75 girls at a summer camp were asked to complete a survey about their favorite outdoor activity. 27 girls chose swimming and 32

Oduvanchick [21]

ANSWER

Find out the expression gives the percent of survey participants who chose swimming.

To proof

As given

75 girls at a summer camp were asked to complete a survey about their favorite outdoor activity.

27 girls chose swimming

32 girls chose hiking.

FORMULA

$Percentage = \frac{Part\times100}{whole}$

total girls = 75

girls chose swimming = 27

put in the formula

$= \frac{27\times100}{75}$

= 36%

36% of survey participants who chose swimming

Hence proved

3 0

3 years ago

Read 2 more answers

An electronics company produces transistors, resistors, and computer chips. Each transistor requires 3 units of copper, 1 unit

padilas [110]

Answer:

An electronics company can be produce 350 transistors and 340 computer chips, they can´t produce resistors.

Step-by-step explanation:

1. We will name the variables for transistors, resistors and the computer chips.

a = Transistors

b= Resistors

c = Computer chips

2. We propose three linear equations, one for the copper, one for the zinc and one for the glass.

$\left \{ {{3a+3b+2c=1730} \atop {a+2b+c=690}}\atop {2a+b+2c=1380}} \right.$

3. We write the matrix form as Ax=d

$A=\left(\begin{array}{ccc}3&3&2\\1&2&1\\2&1&2\end{array}\right)$

$x=\left(\begin{array}{ccc}a\\b\\c\end{array}\right)$

$A=\left(\begin{array}{ccc}1730\\690\\1380\end{array}\right)$

With this formula the solution of x is $x=\frac{d}{A}$ or $x=A^{-1}d$

4. We will find the inverse matrix $A^{-1}$ using the formula:

$A^{-1} = \frac{1}{detA} (C_{A})^{T}$

a. det A

$det A=\left[\begin{array}{ccc}3&3&2\\1&2&1\\2&1&2\end{array}\right] =3*(4-1)-3*(2-2)+2*(1-4)=9-0-6=3$

b. $(C_{A})^{T}$

$C_{A}=\left(\begin{array}{ccc}4-1&.(2-2)&1-4\\-(6-2)&6-4&-(3-6)\\3-4&-(3-2)&6-3\end{array}\right)$

$C_{A}=\left(\begin{array}{ccc}3&.0&-3\\-4&2&3\\-1&-1&3\end{array}\right)$

$(C_{A}) ^T=\left(\begin{array}{ccc}3&0&-3\\-4&2&3\\-1&-1&3\end{array}\right)^T$

$(C_{A}) ^T=\left(\begin{array}{ccc}3&-4&-1\\0&2&-1\\-3&3&3\end{array}\right)$

c. $A^{-1}$

$A^{-1}=\frac{1}{3} \left(\begin{array}{ccc}3&-4&-1\\0&2&-1\\-3&3&3\end{array}\right)$

5. As $x=\frac{d}{A}$ or $x=A^{-1}d$ , the solution of x is:

$x=\frac{1}{3}\left(\begin{array}{ccc}3&-4&-1\\0&2&-1\\-3&3&3\end{array}\right)\left(\begin{array}{ccc}1730\\690\\1380\end{array}\right)$

$x=\frac{1}{3}\left(\begin{array}{ccc}(3*1730)+(-4*690)+(-1*1380)\\(0*1730)+(2*690)+(-1*1380)\\(-3*1730)+(3*690)+(3*1380)\end{array}\right)$

$x=\frac{1}{3}\left(\begin{array}{ccc}1050\\0\\1020)\end{array}\right)$

$X=\left[\begin{array}{ccc}350\\0\\340\end{array}\right]$

Therefore:

a= 350 Transistors

b=0 Resistors

c=340 Computer chips

4 0

3 years ago

Can someone answer this problem fast for me please

agasfer [191]

$1 \times {3}^{100}$

8 0

3 years ago

Solve for k pls ! extra letters for the question: whfjndnfnfn

makvit [3.9K]

Answer:

k=5

Step-by-step explanation:

hope this was helpful!! c:

8 0

3 years ago

Helppppppppppppppppppppppppppp

Otrada [13]

The equation is:
y = 10 sin(π/15 t) + 30
where 30 represents the initial height of the blade above the ground and π/15 represents the period as we are given that the blade completes two rotation every minute.Finally the 10 represents the length of the blades.

Hope this helps :)

7 0

3 years ago