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melomori [17]
3 years ago
12

An athlete eats 75g of protein per day while training. How much protein will she eat during 23 days of training? Write your answ

er in kilograms.
Mathematics
2 answers:
OverLord2011 [107]3 years ago
5 0
K ⇒ Kilograms
  H 
    D
      B ⇒ grams
        D
          C
            M
75 ×23= 1725
distance between Kilo. and grams is 3 jumps
so you jump the decimal 3 jumps to the left
Answer: 1.725 Kilograms of protein <span />
amid [387]3 years ago
3 0
You multiply 75 by 23 to get 1725 and since a kilogram has 1000 grams in it, the athlete eats 1.725 kg of protein.
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Two consecutive integers have a product of 12. What is the initial equation that would be used
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Answer:

x(x+1) = 12

Step-by-step explanation:

If a number is x then it's consecutive number will be x + 1.

And their product x(x+1)

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In the rectangle below, SU= 4x-2, RT = 5x-10, and m ZSVT= 84º.
stepladder [879]

Answer:

RV = 15, ∠ VUR = 48°

Step-by-step explanation:

The diagonals of a rectangle are congruent , so

RT = SU , that is

5x - 10 = 4x - 2 ( subtract 4x from both sides )

x - 10 = - 2 ( add 10 to both sides )

x = 8

Then

RT = 5x - 10 = 5(8) - 10 = 40 - 10 = 30

The diagonals bisect each other , then

RV = 0.5 × 30 = 15

---------------------------------------------------------------

∠ RVU = ∠ svt = 84° ( vertical angles )

RV = UV ( diagonals are congruent and bisect each other )

Then Δ RVU is isosceles with base angles congruent , then

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4.Is it sometimes, always, or never true that, if A and B both have dimensions n x n , AB=BA ? Explain.
REY [17]

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Step-by-step explanation:

I guess that here we have two matrices, A and B, that are nxn.

We can see that if those matrices can conmutate, then we can try it with some simple matrices.

A = \left[\begin{array}{ccc}1&0\\0&-1\end{array}\right] . B =  \left[\begin{array}{ccc}2&0\\1&1\end{array}\right]

Here, we would have that:

AB =  \left[\begin{array}{ccc}2&0\\-1&-1\end{array}\right]

BA =  \left[\begin{array}{ccc}2&0\\1&-1\end{array}\right]

You can see that AB and BA are different, then the statement is not always true.

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AB =  \left[\begin{array}{ccc}ac&0\\0&bd\end{array}\right] = BA

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