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r-ruslan [8.4K]
3 years ago
11

How does antifreeze rely on colligative properties to work?

Chemistry
1 answer:
oksano4ka [1.4K]3 years ago
4 0

Answer:

C. it causes freezing point depression which requires the gasoline to reach a much lower temperature before freezing

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Please include an explanation
Vesna [10]

Answer:

The explanation to your question is below.

Explanation:

In thermochemistry, reactions are classify in two groups.

- Endothermic reactions: are reactions that need energy (heat) from the surroundings to happen. If they are not heated, the products will not form.

Example:

                        2 H₂O + energy ⇒ 2H₂  + O₂

-Exothermic reactions: are reactions that release energy to the surroundings. They happen spontaneously.

Example:

                       CH₄  + 2O₂   ⇒   CO₂   +  2H₂O + energy (heat)

4 0
3 years ago
Where do proteins get the energy to combine co2 and other compounds in the calvin cycle?
Elza [17]
From the atmosphere
Hope this helps!
7 0
3 years ago
which two elements are most likely to form an ionic bond? krypton and lithium, magnesium and silicon, calcium and potassium, iod
Bingel [31]
Iodine, and chlorine I think
6 0
4 years ago
Which of the following best describes repulsions?
poizon [28]
A. to push each other away
3 0
3 years ago
What mass of potassium bromide (in grams) do you need to make 250.0 mL of a 1.50 M potassium bromide solution?
Vedmedyk [2.9K]

Answer:

44.63g

Explanation:

First, let us calculate the number of mole of KBr in 1.50M KBr solution.

This is illustrated below:

Data obtained from the question include:

Volume of solution = 250mL = 250/1000 = 0.25L

Molarity of solution = 1.50M

Mole of solute (KBr) =.?

Molarity is simply mole of solute per unit litre of solution

Molarity = mole /Volume

Mole = Molarity x Volume

Mole of solute (KBr) = 1.50 x 0.25

Mole of solute (KBr) = 0.375 mole

Now, we calculate the mass of KBr needed to make the solution as follow:

Molar Mass of KBr = 39 + 80 = 119g/mol

Mole of KBr = 0.375 mole

Mass of KBr =?

Mass = number of mole x molar Mass

Mass of KBr = 0.375 x 119

Mass of KBr = 44.63g

Therefore, 44.63g of KBr is needed to make 250.0mL of 1.50 M potassium bromide (KBr) solution

8 0
3 years ago
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