Answer:
Explanation:
Slow but able to move past one another
Answer:
386.45 K
Explanation:
We can solve this problem by using <em>Charles' law</em>, which states that at constant pressure:
Where subscript 1 stands for initial conditions of volume and temperature, while 2 stands for the final ones. Meaning that in this case:
- T₁ = 36 °C ⇒ 36 +273.16 = 309.16 K
We<u> input the data</u>:
- 2.0 L * T₂ = 2.5 L * 309.16 K
And <u>solve for T₂</u>:
Answer : The rate of the reaction if the concentration of is doubled is, 0.006 M/s
Explanation :
Rate law : It is defined as the expression which expresses the rate of the reaction in terms of molar concentration of the reactants with each term raised to the power their stoichiometric coefficient of that reactant in the balanced chemical equation.
The balanced equations will be:
In this reaction, and are the reactants.
The rate law expression for the reaction is:
As we are given that:
= concentration of = 0.100 M
= concentration of = 0.100 M
Rate = 0.0030 M/s
Now put all the given values in the above expression, we get:
Now we have to calculate the rate of the reaction if the concentration of is doubled.
Thus, the rate of the reaction if the concentration of is doubled is, 0.006 M/s