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Ronch [10]
3 years ago
11

1. The multiplicative inverse of 5/9 is.....a-9/5b-9/5c-3/9d-None of these​

Chemistry
2 answers:
Luda [366]3 years ago
5 0

Answer:

None of these cause the correct answer is 9/-5

Tpy6a [65]3 years ago
4 0
The Answer Is None Of These
But The Answer Is -5/9
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<span>As heat energy reaches an object it can be absorbed in a similar manner to the way sponges absorb water. Heat enters an object, warming it. The longer the object is exposed to the heat source, the more heat it absorbs.</span>
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3 years ago
Jose times how long sugar takes to dissolve in warm water. he conducts four trials of his experiment. what should he conclude fr
mylen [45]

He can conclude that his experiment has very low precision.

<h3>What is Precision ?</h3>

Precision is defined as the degree of refinement with which an operation is performed or a measurement .

Precision is how close the exact answers are together.

As, the answers are increasing in time.

None of the answers are similar to one another.

Hence, He can conclude that his experiment has very low precision.

Learn more about Precision here ;

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7 0
2 years ago
What do you think is responsible for the color produced in the flame, the metal atom or what is attached to the metal atom?
zlopas [31]

Answer:

metal Atom

Explanation:

every transition metal atom are responsible for the flame color. Some metal are also confirmed by flame test.

7 0
3 years ago
What is the period tables purpose?
alexgriva [62]
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4 0
3 years ago
What is the electric force on a proton 2.5 fmfm from the surface of the nucleus? Hint: Treat the spherical nucleus as a point ch
sammy [17]

Explanation:

It is known that charge on xenon nucleus is q_{1} equal to +54e. And, charge on the proton is q_{2} equal to +e. So, radius of the nucleus is as follows.

            r = \frac{6.0}{2}

              = 3.0 fm

Let us assume that nucleus is a point charge. Hence, the distance between proton and nucleus will be as follows.

              d = r + 2.5

                 = (3.0 + 2.5) fm

                 = 5.5 fm

                 = 5.5 \times 10^{-15} m     (as 1 fm = 10^{-15})

Therefore, electrostatic repulsive force on proton is calculated as follows.

              F = \frac{1}{4 \pi \epsilon_{o}} \frac{q_{1}q_{2}}{d^{2}}

Putting the given values into the above formula as follows.

           F = \frac{1}{4 \pi \epsilon_{o}} \frac{q_{1}q_{2}}{d^{2}}

              = (9 \times 10^{9}) \frac{54e \times e}{(5.5 \times 10^{-15})^{2}}

              = (9 \times 10^{9}) \frac{54 \times (1.6 \times 10^{-19})^{2}}{(5.5 \times 10^{-15})^{2}}

              = 411.2 N

or,           = 4.1 \times 10^{2} N

Thus, we ca conclude that 4.1 \times 10^{2} N is the electric force on a proton 2.5 fm from the surface of the nucleus.

8 0
4 years ago
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