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Ronch [10]
3 years ago
11

1. The multiplicative inverse of 5/9 is.....a-9/5b-9/5c-3/9d-None of these​

Chemistry
2 answers:
Luda [366]3 years ago
5 0

Answer:

None of these cause the correct answer is 9/-5

Tpy6a [65]3 years ago
4 0
The Answer Is None Of These
But The Answer Is -5/9
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A reaction produces 0.883 moles of H₂O. How many molecules are produced?
prisoha [69]
The answer is 5.32 × 10²³ molecules

<span>Avogadro's number is the number of units (atoms, molecules) in 1 mole of substance:
</span>6.023 <span>× 10²³ units per 1 mole

We have 0.883 moles.
If 1 mole has </span>6.023 × 10²³ molecules, 0.883 moles will have x molecules:
1 mole : 6.023 × 10²³ molecules = 0.883 moles : x

x = 6.023 × 10²³ molecules * 0.883 moles : 1 mole = 5.32 × 10²³ molecules
6 0
3 years ago
When the moon moves directly between the sun and Earth and casts its shadow over part of Earth, you are
chubhunter [2.5K]

Answer:C

Explanation:you are seeing a lunar eclipse when the moon moves directly between the sun and the earth and casts a shadow. Hope this helps!

7 0
2 years ago
Read 2 more answers
True or false ? <br>an insoluble base will react with an acid. <br>​
Leno4ka [110]

Answer:

true maybe

Explanation:

#CarryOnLearning

7 0
2 years ago
When the following oxidation–reduction reaction in acidic solution is balanced, what is the lowest whole-number coefficient for
ruslelena [56]

Answer:

b. 16, reactant side

Explanation:

Let's consider the following redox reaction.

MnO₄⁻(aq) + I⁻(aq) → Mn²⁺(aq) + I₂(s)

We can balance it using the ion-electron method.

Step 1: Identify both half-reactions

Reduction: MnO₄⁻(aq) → Mn²⁺(aq)

Oxidation: I⁻(aq) → I₂(s)

Step 2: Perform the mass balance, adding H⁺(aq) and H₂O(l) where appropriate

MnO₄⁻(aq) + 8 H⁺(aq) → Mn²⁺(aq) + 4 H₂O(l)

2 I⁻(aq) → I₂(s)

Step 3: Perform the charge balance, adding electrons where appropriate

MnO₄⁻(aq) + 8 H⁺(aq) + 5 e⁻ → Mn²⁺(aq) + 4 H₂O(l)

2 I⁻(aq) → I₂(s)  + 2 e⁻

Step 4: Multiply both half-reactions by numbers so that the number of electrons gained and lost are equal

2 × (MnO₄⁻(aq) + 8 H⁺(aq) + 5 e⁻ → Mn²⁺(aq) + 4 H₂O(l))

5 × (2 I⁻(aq) → I₂(s)  + 2 e⁻)

Step 5: Add both half-reactions and cancel what is repeated on both sides

2 MnO₄⁻(aq) + 16 H⁺(aq) + 10 e⁻ + 10 I⁻(aq) → 2 Mn²⁺(aq) + 8 H₂O(l) + 5 I₂(s)  + 10 e⁻

The balanced reaction is:

2 MnO₄⁻(aq) + 16 H⁺(aq) + 10 I⁻(aq) → 2 Mn²⁺(aq) + 8 H₂O(l) + 5 I₂(s)

5 0
2 years ago
Convert 1000mg=__g 1L=__mL 160cm=__mm 1.4km=__m 109g=__kg 250m=__km 80cm=__m 75mL=__L 5.6m=__cm 6.5g=__mg 170.4m=__cm 564Dg=__g
Snowcat [4.5K]

Answer:

1000mg= 1g

1L= 1000 mL

160cm = 1600mm

1.4km= 1400m

109 g = 0.109kg

250m= 0.250 km

80cm= 0.8 m

75mL= 0.075L

5.6m= 560 cm

6.5g= 6500mg

170.4m= 17040 cm

564 Dg = 5640 g

58 dg = 5800 mg

600 L=  0.6 KL

0.0923Km= 92300 mm

Explanation:

1 mg = 1x10⁻³ g

1 g = 1000 mg

1 g = 10 dg

1 g = 1x10⁻³ kg

1 Dg = 10 g

1 dg = 100 mg

1 L = 1000 mL

1 L = 1x10⁻³ KL

1 mL = 1x10⁻³ L

1 km = 1000 m

1 km = 1x10⁶ mm

1 m = 1x10⁻³ km

1 cm = 1x10⁻² m

1 cm = 10 mm

5 0
3 years ago
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