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Stells [14]
3 years ago
11

Y=3x-2 solve for x plz help 40 points!!!

Mathematics
1 answer:
Svetlanka [38]3 years ago
6 0

Answer:

x=\frac{y+2}{3}

Step-by-step explanation:

1) since we are solving for x we want x to be the ONLY thing on the other side of the equation symbol:

for ex. x=

2) to do this, we need to eliminate -2, we eliminate -2 by adding 2 on both sides:

y+2=3x-2+2

y+2=3x

remove 3 by dividing it on both sides(opposite operation)

\frac{y+2}{3}=x

this is our final equation since we have solved for x

hope this helps

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The owner of a 4000-gal oil truck loads the truck with gasoline and keroseno. The profit on each gallon of gasoline is 16e and o
lilavasa [31]

Answer:

There were 35 gallons of gasoline and 500 gallons of kerosene.

Step-by-step explanation:

<u>Step 1: Write data for equation 1</u>

<em>Let gallons of kerosene be x</em>

<em>Let gallons of gasoline be y</em>

<em>Total capacity of truck is 4000</em>

<u>Step 2: Form equation 1</u>

x + y = 4000

<u>Step 3: Write data for equation 2</u>

<em>Profit of total gallons of kerosene is 0.12x</em>

<em>Profit of total gallons of gasoline is 16y</em>

<em>Total profit is $620</em>

<u>Step 4: Form equation 2</u>

0.12x + 16y = 620

<u>Step 5: Find x in terms of y from equation 1</u>

x + y = 4000

x = 4000 - y

<u>Step 6: Substitute value of x in equation 2</u>

0.12x + 16y = 620

0.12 (4000 - y) + 16y = 620

480 - 12y + 16y = 620

4y = 620 - 480

y = 140/4

y = 35

<u>Step 7: Substitute value of y in equation 1 to find x</u>

0.12x + 16y = 620

0.12x + 16 ( 35 ) = 620

0.12x = 60

x = 500

There were 35 gallons of gasoline and 500 gallons of kerosene.

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6 0
3 years ago
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Andrews [41]

Answer:

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Step-by-step explanation:

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3 years ago
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Dairy cows at large commercial farms often receive
IrinaK [193]

Answer:

a) The 99% confidence interval for the true mean milk production is (26.35 kg/d, 29.65 kg/d).

b) They would need to use a confidence level of 94.52%.

Step-by-step explanation:

a)

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1-0.99}{2} = 0.005

Now, we have to find z in the Ztable as such z has a pvalue of 1-\alpha.

So it is z with a pvalue of 1-0.005 = 0.995, so z = 2.575

Now, find M as such

M = z*\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample. So

M = 2.575*\frac{2.25}{\sqrt{12}} = 1.65

The lower end of the interval is the mean subtracted by M. So it is 28-1.65 = 26.35 kg/d

The upper end of the interval is the mean added to M. So it is 28 + 1.65 = 29.65 kg/d.

The 99% confidence interval for the true mean milk production is (26.35 kg/d, 29.65 kg/d).

(b) If the farms want the confidence interval to be no wider than 1.25 kg/d, what level of confidence would they need to use?

Now we want to find the value of z when M = 1.25. So:

1.25 = z*\frac{2.25}{\sqrt{12}}

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So the confidence level should be 1 - 2*(1-0.9726) = 0.9452

They would need to use a confidence level of 94.52%.

3 0
3 years ago
Please help!! solve for x
stira [4]

Step-by-step explanation:

By Intersecting Chords Theorem,

9 * 4x = 8 * (4x + 2).

=> 36x = 32x + 16

=> 4x = 16, x = 4. (2)

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3 years ago
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The greatest number of binders is 5, the greatest number of notebooks is 10. If she buys 7 notebooks then she can only buy 1.
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